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Answer in brief. How much heat is evolved when 12 g of CO reacts with NO2? The reaction is: 4CO(g) 2NO2(g) → 4CO2(g) + N2(g), ΔrH° = - 1200 kJ

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प्रश्न

Answer in brief.

How much heat is evolved when 12 g of CO reacts with NO2? The reaction is:

4CO(g)  2NO2(g) → 4CO2(g) + N2(g), ΔrH° = - 1200 kJ

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उत्तर

Given: ΔrH° = - 1200 kJ, Mass of CO = 12 g

To find: Heat evolved when 12g of CO reacts with NO2

Calculation:

According to the given reaction, 1200 kJ of heat is evolved when 4 moles of CO react with NO2. So heat evolved per mole is `(1200  "kJ")/(4  "mol")` = 300 kJ mol-1

Molar mass of CO = 12 + 16 = 28 g mol–1

Number of moles of CO = `"Mass of CO"/"Molar mass of CO" = (12 "g")/(28 "g mol"^-1)`= 0.4286 mol

So, heat evolved when 0.4286 moles of CO reacts

= 0.4286 mol × 300 kJ mol-1 = 128.58 kJ

The heat evolved when 12 g of CO reacts with NO2 is 128.58 kJ.

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पाठ 4: Chemical Thermodynamics - Exercises [पृष्ठ ८८]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
पाठ 4 Chemical Thermodynamics
Exercises | Q 3.9 | पृष्ठ ८८

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