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प्रश्न
An element X has the following isotopic composition 200X = 90%, 199X = 8% and 202X = 2%. The weighted average atomic mass of the element X is closest to
पर्याय
201 u
202 u
199 u
200 u
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उत्तर
200 u
Explanation:
X = `((200 xx 90) + (199xx 8) + (202 xx 2))/100`
= 199.96
= 200 u
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