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An alpha particle is projected vertically upward with a speed of 3.0 × 104 km s−1 in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force - Physics

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प्रश्न

An alpha particle is projected vertically upward with a speed of 3.0 × 104 km s−1 in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the α-particle.

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उत्तर

Given:
Upward speed of the alpha particle, v = 3 × 104 km/s = 3 × 107 m/s

Magnetic field, B = 1.0 T

The direction of the magnetic field is from south to north.

Charge of the alpha particle, q = 2e,

where e is the charge of an electron.

q = 2 × 1.6 × 10−19 C,

Magnetic force acting on the α-particle,

`vecF = qvecv xx vecB  sin 90^circ`

= `2xx1.6xx10^-19xx3xx10^7 xx 1 xx 1`

= `9.6xx10^-12` N , towards west 


The direction of magnetic force can be found using Fleming's left-hand rule.
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पाठ 12: Magnetic Field - Exercises [पृष्ठ २३०]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 12 Magnetic Field
Exercises | Q 1 | पृष्ठ २३०
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