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An alkali metal A gives a compound B (molecular mass = 40) on reacting with water. The compound B gives a soluble compound C on treatment - Science

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प्रश्न

An alkali metal A gives a compound B (molecular mass = 40) on reacting with water. The compound B gives a soluble compound C on treatment with aluminium oxide. Identify A, B and C and give the reaction involved.

थोडक्यात उत्तर
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उत्तर

Alkali metal sodium when reacting with water gives a chemical compound sodium hydroxide. When sodium hydroxide is treated with aluminium oxide gives a soluble compound sodium aluminate.

Hence, A is sodium, B is sodium hydroxide and C is sodium aluminate.

`"Al"_2"O"_3("s") + 2"NaOH"("aq") -> 2"NaAlO"_2("aq") + "H"_2"O"("l")`

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पाठ 3: Metals and Non-metals - Short Answer Questions [पृष्ठ २६]

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एनसीईआरटी एक्झांप्लर Science [English] Class 10
पाठ 3 Metals and Non-metals
Short Answer Questions | Q 54. | पृष्ठ २६

संबंधित प्रश्‍न

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(b) Chlorine
(c) Oxygen
(d) Nitrogen


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(a) CuSO4
(b) FeSO4
(c) ZnSO4
(d) Al2(SO4)3


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i. What is the nature of oxide E2O ?
ii. Write the name of element ‘E’.


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Fill in the following blank with suitable word:

The white powder formed when magnesium ribbon burns in oxygen is of ....................


Fill in the following blank with suitable word:

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Calcium is a ................. reactive metal than sodium.


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(b) K and C
(c) Na and S
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CuSO4(aq) + Fe(s) → FeSO4(aq) + Cu(s)

FeSO4(aq) + Zn(s) → ZnSO4(aq) + Fe(s)

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