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प्रश्न
An aircraft of wing span of 60 m flies horizontally in earth’s magnetic field of 6 × 10−5 T at a speed of 500 m/s. Calculate the e.m.f. induced between the tips of the wings of the aircraft.
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उत्तर
e.m.f. = B⋅v⋅l
Given:
The magnetic field strength, B = 6 × 10−5 T,
The speed of the aircraft, v = 500 m/s,
The wing span of the aircraft, l = 60 m.
To find:
e.m.f. (e) = ?
Formula:
e = B l v
Substituting given values into the formula:
e.m.f. (e) = 6 × 10−5 T × 500 m/s × 60 m
e.m.f. (e) = 6 × 10−5 × 30000
e.m.f. (e) = 1.8 V
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