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प्रश्न
Account for the following
Bi(V) is a stronger oxidizing agent than Sb(V).
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उत्तर
Because of inert pair effect +5 oxidation state is less stable in Bi than in Sb. So the Bi in +5 state will immediately get reduced to its +3 state and thus will be a better oxidizing agent than +5 state of Sb.
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संबंधित प्रश्न
Write four points of differences between properties of nitrogen and other elements of group 15.
Account for the following:
N2 is less reactive at room temperature.
Account for the following: Reducing character increases from NH3 to BiH3.
Arrange the following in the increasing order of property mentioned :
H3PO3, H3PO4, H3PO2 (Reducing character)
Give reasons When Cl2 reacts with the excess of F2, ClF3 is formed and not FCl3.
Give a reason for the following:
E° value for (Mn2+|Mn) is negative whereas for (Cu2+|Cu) is positive.
Ionic radii (in Å) of As3+, Sb3+ and Bi3+ follow the order:
The p-block element of group 15 that forms predominantly basic oxide is _____________.
H2S is more acidic than H2O because ____________.
Which acid of the following pair would you expect to be stronger?
F−CH2−COOH or CH3−COOH
