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प्रश्न
Account for the following
Bi(V) is a stronger oxidizing agent than Sb(V).
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उत्तर
Because of inert pair effect +5 oxidation state is less stable in Bi than in Sb. So the Bi in +5 state will immediately get reduced to its +3 state and thus will be a better oxidizing agent than +5 state of Sb.
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संबंधित प्रश्न
The element that does NOT exhibit allotropy is
- As
- Sb
- Bi
- N
Explain how does nitrogen exhibit anomalous behaviour amongst group 15 elements.
The group 15 element having inner electronic configuration as of argon is-
(a) Phosphorous (z = 15)
(b) Antimony (z =51)
(c) Arsenic (z = 33)
(d) Nitrogen (z = 7)
The oxidation state of nitrogen in dinitrogen trioxide is ____
(a) + 1
(b) + 2
(c) + 3
(d) + 4
Which of the following is the strongest reducing agent?
H2S is more acidic than H2O because ____________.
Which of the following statements is true?
If chlorine gas is passed through hot NaOH solution, two changes are observed in the oxidation number of chlorine during the reaction. These are :
(i) 0 to +5
(ii) 0 to +3
(iii) 0 to –1
(iv) 0 to +1
Which of the following options are not in accordance with the property mentioned against them?
| (i) | \[\ce{F2 > Cl2 > Br2 > I2}\] | Oxidising power. |
| (ii) | \[\ce{MI > MBr > MC1 > MF}\] | Ionic character of metal halide. |
| (iii) | \[\ce{F2 > Cl2 > Br2 > I2}\] | Bond dissociation enthalpy. |
| (iv) | \[\ce{HI < HBr < HCI < HF}\] | Hydrogen-halogen bond strength. |
In which of the following compounds the metal is in lowest oxidation state?
