मराठी

A Trader Fixes the Selling Price of His Goods at 50% Above the Cost Price. He Sells Half of His Stock at this Price, a Quarter of His Stock at a Discount of 20% on the Original Selling Price - Mathematics

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प्रश्न

A trader fixes the selling price of his goods at 50% above the cost price. He sells half of his stock at this price, a quarter of his stock at a discount of 20% on the original selling price, and the rest at a discount of 36% on the original selling price. Find the gain percent altogether.

बेरीज
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उत्तर

Let the C.P. of each article bought = Rs.100
Let the number of articles bought = x
∴ C.P. of the articles = Rs.100x
M.P. of the articles
= Rs.100 + 50% of Rs.100
= Rs.150
Stage 1 :
No. of articles sold at Rs.150 = `x/(2)`

∴ S.P. of `x/(2)`articles

= Rs.`(150 xx x/2)`
= Rs.75x
Stage 2 :
Discount
= 20% of Rs.150
= `(20)/(100) xx "Rs."150`
= Rs.30
∴ S.P. 
= Rs.150 - Rs.30
= Rs.120
No. of articles sold at Rs.120 = `x/(4)`

∴ S.P. of `x/(2)`articles

= Rs.`(120 xx x/4)`
= Rs.30x
Stage 3 :
Discount
= 36% of Rs.150
= `(36)/(100) xx "Rs."150`
= Rs.54
No. of articles sold at Rs.96 = `x/(4)`

∴ S.P. of `x/(2)`articles

= Rs.`(96 xx x/4)`
= Rs.24x
Total S.P. of all articles
= Rs.75x + Rs.30x + Rs.24x
= Rs.129x
∵ S.P. > C.P., therefore there is a gain
Gain
= Rs.129x - Rs.100x
= Rs,29x
Gain %
= `"gain"/"C.P." xx 100`

= `(29x)/(100x) xx 100`
= 29%.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Profit , Loss and Discount - Exercise 2.4

APPEARS IN

फ्रँक Mathematics [English] Class 9 ICSE
पाठ 2 Profit , Loss and Discount
Exercise 2.4 | Q 19

संबंधित प्रश्‍न

After offering discount of 10% on marked price, a customer gets total discount of 17 rupees. To find the cost price for the customer, fill in the following boxes with appropriate numbers and complete the activity.

Suppose, marked price of the item = 100 rupees

Therefore, for customer that item costs `square` - `square`  = 90 rupees

Hence, when the discount is `square` then the selling price is `square` rupees. 

Suppose when the discount is `square` rupees, the selling price is x rupees.

∴ `x/square=square/square`

∴ x = `(squarexxsquare)/square`

∴ x = `square`

∴ the customer will get the item for 153 rupees.


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