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प्रश्न
A toy is in the form of a cone surmounted on a hemisphere. The diameter of the base and the height of cone are 6cm and 4cm. determine surface area of toy?
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उत्तर
Given height of cone (h) = 4cm
Diameter of cone (d) = 6cm
∴Radius (r) =`6/2 =3 cm`

Let ‘l’ be slant height of cone
`l=sqrt(r^2+h^2)`
`=sqrt(3^2+4^2) =5cm`
l = 5cm
∴ Slant height of cone (l) = 5cm.
Curved surface area of cone (S1) = πrl
S1 = π(3)(5) = 47.1cm2
Curved surface area of hemisphere (S2) = 2πr2
`S_2=2pi(3)^2=56.52cm^2`
∴Total surface area(S) = S1 + S2
= 47.1 + 56.52
= 103.62cm2
∴ Curved surface area of toy = 103.62cm2
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Khurja is a city in the Indian state of Uttar Pradesh famous for the pottery. Khurja pottery is traditional Indian pottery work which has attracted Indians as well as foreigners with a variety of tea sets, crockery and ceramic tile works. A huge portion of the ceramics used in the country is supplied by Khurja and is also referred as "The Ceramic Town". One of the private schools of Bulandshahr organised an Educational Tour for class 10 students to Khurja. Students were very excited about the trip. Following are the few pottery objects of Khurja.
Students found the shapes of the objects very interesting and they could easily relate them with mathematical shapes viz sphere, hemisphere, cylinder etc. |
Maths teacher who was accompanying the students asked the following questions:
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- If in the cylindrical jar full of water, a conical funnel of the same height and same diameter is immersed, then how much water will flow out of the jar?
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