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A Torsional Pendulum Consists of a Solid Disc Connected to a Thin Wire (α = 2.4 × 10–5 °C–1) at Its Centre.

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प्रश्न

A torsional pendulum consists of a solid  disc connected to a thin wire (α = 2.4 × 10–5°C–1) at its centre. Find the percentage change in the time period between peak winter (5°C) and peak summer (45°C).
  

थोडक्यात उत्तर
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उत्तर

Given:
Coefficient of linear expansion of the wire, α = 2.4 × 10–5 °C–1
Let I0 be the moment of inertia of the torsional pendulum at 0 °C.
If K is the torsional constant of the wire, then time period of torsional pendulum (T):

`T = 2pi sqrt(1/K)`...(1)

Here, I = moment of inertia after change in temperature
When the temperature is changed by Δθ, moment of inertia (I),

l = l0(1+2αΔθ)

On substituting the value of I  in equation(1), we get:

`T = 2 pi sqrt( I_0(1+2αΔθ))/sqrt K`

In winter ,  Δθ = 5 °C

∴ Time period , (T1)

= `2pi sqrt( I_0(1+2αΔθ))/sqrt K`

In summer , Δθ = 45 °C 

Time period (T2)

`=2pi sqrt( I_0(1+2αΔθ))/sqrt K`

So, 

`T_2/T_1 = sqrt(1+90α)/sqrt(1+10α)`

=`sqrt(1+90 xx 2.4 xx 10^-5)/sqrt(1+10 xx 2.4 xx 10^-5)`

`=> T_2/T_1 = sqrt(1.00216)/sqrt(1.00024)`

% change = `(T_2/T_1 -1) xx 100`

= 0.0959 %

⇒ % change in time period ≈ 9.6 ×  10-2 %

Therefore, the percentage change in time period of a torsional pendulum between peak winters and peak summers is 9.6 × 10–2  % .

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पाठ 23: Heat and Temperature - Exercises [पृष्ठ १४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 23 Heat and Temperature
Exercises | Q 33 | पृष्ठ १४

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