Advertisements
Advertisements
प्रश्न
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
Advertisements
उत्तर
Initial velocity, u = 0 m s-1
Final velocity, v =?
Height of the tower, h = 19.6 m
Acceleration due to gravity, g = 9.8 m s-2
Using the equation, v2 - u2 = 2gs = 2gh
v2 - 0 = 2 × 9.8 m s-2 × 19.6 m
v2 = 19.6 m s-2 × 19.6 m
v2 = (19.6)2 m2 s-2
or v = 19.6 m s-1
APPEARS IN
संबंधित प्रश्न
What do you mean by acceleration due to gravity?
What is the acceleration of free fall?
A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.
Why does a sharp knife cut objects more effectively than a blunt knife ?
What will be the weight of a person on earth, who weighs 9N on the moon?
How is the acccelaration due to gravity on the surface of the earth realted to its mass and radius ?
An object falling freely from rest reaches ground in 2 s. If acceleration due to gravity is 9.8 m s-2, then the velocity of object on reaching the ground will be
In vacuum, all freely falling objects have the same force. Is it true?
Explain why:
Objects fall to the earth.
Right or wrong sentence:
The value of gravitational acceleration at the centre of earth is zero.
