Advertisements
Advertisements
प्रश्न
A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
Advertisements
उत्तर
Initial velocity (u) = 40m/s
g = −10m/s2
Final velocity at maximum height (v) = 0
Third equation of motion
v2 = u2 + 2gh
0 = 402 + 2 × (−10) × h
1600 = 20h
80m = h
Max Distance = 80m
Total distance travelled by the stone = 80 + 80
= 160m
Because the stone was thrown upwards, but it came back.
Hence, total displacement = 0
APPEARS IN
संबंधित प्रश्न
Which force is responsible for the moon revolving round the earth ?
Name the force which pulled the apple off Isaac Newton’s tree.
A stone is thrown vertically upwards with initial velocity u reaches a height ‘h’ before coming down. Show that the time taken to go up is the same as the time taken to come down.
A force of 15 N acts on a body of mass 2 kg. Calculate the acceleration produced.
A car is moving with a uniform velocity 30 ms-1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate the following values : The retardation produced in car.
How is the acccelaration due to gravity on the surface of the earth realted to its mass and radius ?
Right or wrong sentence:
The value of gravitational acceleration at the centre of earth is zero.
Right or wrong sentence.
Free fall of an object does not depend on the mass of the object.
Write scientific reasons.
The value of gravitational acceleration (g) is taken to be -g when studying the motion of an object thrown upwards in a straight line.
Write the acceleration due to gravity value on the surface of Earth.
