Advertisements
Advertisements
प्रश्न
A speeding car changes its velocity from 108 kmh−1 to 36 kmh−1 in 4 s. Calculate its deceleration in
- ms−2
- kmh−2.
Advertisements
उत्तर
Initial velocity = u = 108 kmh−1
u = `108xx5/18` m−1
u = 30 ms−1
Final velocity = v = 36 kmh−1
v = `36xx5/18` ms−1
v = 10 ms−1
Time = t = 4 S
Deceleration = a = `("v"-"u")/"t"`
a = `(10-30)/4`
a = `-20/4` = −5 ms−2
a = `(-5xx3600xx3600)/1000` kmh−2 = −64800 kmh−2
APPEARS IN
संबंधित प्रश्न
What is the Differnece between speed and velocity ?
Abdul, while driving to school, computes the average speed for his trip to be 20 km h−1. On his return trip along the same route, there is less traffic and the average speed is 30 km h−1. What is the average speed for Abdul’s trip?
Under which condition is the magnitude of average velocity equal to average speed ?
Arrange the following speed in increasing order (keeping the least speed first):
An athlete running with a speed of 10 m/s.
A train starting from Railway Station attains a speed of 21 m/s in one minute. Find its acceleration.
A motorcyclist starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3 s. What is his acceleration ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
What is its average speed ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How long does it take to travel 240 m ?
A car is moving on a straight road with uniform acceleration. The speed of the car varies with time as follows :
Time (s) : 0 2 4 6 8 10
Speed (m/s) : 4 8 12 16 20 24
Draw the speed-time graph by choosing a convenient scale. From this graph :
(1) Calculate the acceleration of the car.
(2) Calculate the distance travelled by the car in 10 seconds.
For the motion with uniform velocity , how is the distance travelled related to the time ?
