Advertisements
Advertisements
प्रश्न
A speeding car changes its velocity from 108 kmh−1 to 36 kmh−1 in 4 s. Calculate its deceleration in
- ms−2
- kmh−2.
Advertisements
उत्तर
Initial velocity = u = 108 kmh−1
u = `108xx5/18` m−1
u = 30 ms−1
Final velocity = v = 36 kmh−1
v = `36xx5/18` ms−1
v = 10 ms−1
Time = t = 4 S
Deceleration = a = `("v"-"u")/"t"`
a = `(10-30)/4`
a = `-20/4` = −5 ms−2
a = `(-5xx3600xx3600)/1000` kmh−2 = −64800 kmh−2
APPEARS IN
संबंधित प्रश्न
A snail covers a distance of 100 metres in 50 hours. Calculate the average speed of snail in km/h.
A motorcyclist drives from place A to B with a uniform speed of 30 km h-1 and returns from place B to A with a uniform speed of 20 km h-1. Find his average speed.
Convert a speed of 54 km/h into m/s.
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
What is its average speed ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How far does it travel in 1 second ?
Write the formula to calculate the speed of a body moving along a circular path. Give the meaning of each symbol which occurs in it.
One of the following is not a vector quantity. This one is :
The speed of a car is 72 km h-1. Express it in m s-1.
Draw the shape of the velocity-time graph for a body moving with (a) Uniform velocity and (b) Uniform acceleration.
Draw a diagram to show the motion of a body whose speed remains constant, but velocity changes continuously.
