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प्रश्न
A random sample of 60 observations was drawn from a large population and its standard deviation was found to be 2.5. Calculate the suitable standard error that this sample is taken from a population with standard deviation 3?
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उत्तर
Sample size n = 60
Sample S.D S = 2.5
Population S.D a = 3
The standard error for sample S.D is given by
`sqrt(sigma^2/(2"n")) = sqrt((3)^2/(2(60))`
= `3/sqrt(120)`
= `3/10.954` = 0.27387
= 0.2739
Thus standard error for sample S.D = 0.2739
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संबंधित प्रश्न
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What is statistic?
Define parameter
Explain in detail about simple random sampling with a suitable example
Explain the stratifi ed random sampling with a suitable example
Explain in detail about non-sampling error
State any two demerits of systematic random sampling
Choose the correct alternative:
A ______ of statistical individuals in a population is called a sample
Choose the correct alternative:
A random sample is a sample selected in such a way that every item in the population has an equal chance of being included
Use the data in the Table below that relate to monthly household expenditure (in Rs) on the food of 50 households and
| 1904 | 1559 | 3473 | 1735 | 2760 |
| 2041 | 1612 | 1753 | 1855 | 4439 |
| 5090 | 1085 | 1823 | 2346 | 1523 |
| 1211 | 1360 | 1110 | 2152 | 1183 |
| 1218 | 1315 | 1105 | 2628 | 2712 |
| 4248 | 1812 | 1264 | 1183 | 1171 |
| 1007 | 1180 | 1953 | 1137 | 2048 |
| 2025 | 1583 | 1324 | 2621 | 3676 |
| 1397 | 1832 | 1962 | 2177 | 2575 |
| 1293 | 1365 | 1146 | 3222 | 1396 |
Monthly Household Expenditure (in Rupees) on Food of 50 Households
Find the number of households whose monthly expenditure on food is
(b) more than Rs 3000
(c) between Rs 1500 and Rs 2500
