Question

Determine the standard error of proportion for a random sample of 500 pineapples was taken from a large consignment and 65 were found to be bad

Answer 1

Sample size n = 500

No. of bad pine apples = 65

Sample proportion = P = `65/100` = 0.13

Q = 1 – p

⇒ Q = 1 – 0.13

∴ Q = 0.87

The S.E for sample proportion is given by

S.E = `sqrt("PQ"/"N")`

= `sqrt(((0.13)(0.87))/500)`

= `sqrt(0.1131/500`

= `sqrt(0.0002262)`

= 0.01504

∴ S.E = 0.015

Hence the standard error for sample proportion is S.E = 0.015