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प्रश्न
A radioactive nuclide `""_86^226` Ra decays by emission of two alpha particles, one beta particle and gamma rays. Which of the following is the resulting nuclide X?
पर्याय
223
X
83
218
X
83
218
X
84
217
X
85218
X
85
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उत्तर
218
X
83
Explanation:
Given: Initial nuclide = \(\,^{226}_{86}\mathrm{Ra}\)
Emissions = 2 α-particles, 1 β-particle and γ-rays.
The mass number (A).
Each α-particle decreases the mass number by 4.
\[ A=226 - (2\times4) = 218 \]
The atomic number (Z).
Each α-particle decreases the atomic number by 2, while one β⁻-particle increases it by 1.
\[ Z = 86 - (2\times2) +1 \]
\[ Z = 86 - 4 + 1 = 83 \]
Gamma rays do not change the mass number or atomic number.
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