Advertisements
Advertisements
प्रश्न
A point whose abscissa is −3 and ordinate 2 lies in
पर्याय
First quadrant
Second quadrant
Third quadrant
Fourth quadrant
Advertisements
उत्तर
As we know that
In the first quadrant x > 0, y >0
In the second quadrant x < 0 , y > 0
In the third quadrant x < 0 y < 0
In the fourth quadrant x > 0,y < 0

The point whose abscissa is −3 which is negative and ordinate 2 is positive, so this point lies in the second quadrant.
APPEARS IN
संबंधित प्रश्न
Find the value of k, if the point P (0, 2) is equidistant from (3, k) and (k, 5).
Find the value of x such that PQ = QR where the coordinates of P, Q and R are (6, -1), (1, 3) and (x, 8) respectively.
If A and B are (1, 4) and (5, 2) respectively, find the coordinates of P when AP/BP = 3/4.
If the point C ( - 2,3) is equidistant form the points A (3, -1) and Bx (x ,8) , find the value of x. Also, find the distance between BC
Show that the following points are the vertices of a square:
A (0,-2), B(3,1), C(0,4) and D(-3,1)
Find the possible pairs of coordinates of the fourth vertex D of the parallelogram, if three of its vertices are A(5, 6), B(1, –2) and C(3, –2).
Points (−4, 0) and (7, 0) lie
If the point P(x, 3) is equidistant from the point A(7, −1) and B(6, 8), then find the value of x and find the distance AP.
If three points (0, 0), \[\left( 3, \sqrt{3} \right)\] and (3, λ) form an equilateral triangle, then λ =
Points (1, –1) and (–1, 1) lie in the same quadrant.
