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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0 × 10^−7 m2, and its resistance is measured to be 5.0 Ω. What is the resistivity of the material at

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प्रश्न

A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0 × 10−7 m2, and its resistance is measured to be 5.0 Ω. What is the resistivity of the material at the temperature of the experiment?

संख्यात्मक
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उत्तर

Given: Length of the wire, l = 15 m

Area of cross-section of the wire, A = 6.0 × 10−7 m2

Resistance of the material of the wire, R = 5.0 Ω

To find: Resistivity of the material of the wire ρ = ?

Formula: Resistance is related to resistivity as,

R = `ρ l/A`

ρ = `(RA)/l`

= `(5.0 xx 6.0 xx 10^-7)/15`

= `(30 xx 10^-7)/15`

= 2 × 10−7 Ω m

Therefore, the resistivity of the material is 2 × 10−7 Ω m.

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पाठ 3: Current Electricity - EXERCISES [पृष्ठ १०६]

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एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 3 Current Electricity
EXERCISES | Q 3.4 | पृष्ठ १०६
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 3 Current Electricity
Exercise | Q 3.6 | पृष्ठ १२७

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