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A Magnetic Flux of 8 × 10−4 Weber is Linked with Each Turn of a 200-turn Coil When There is an Electric Current of 4 a in It. Calculate the Self-inductance of the Coil.

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प्रश्न

A magnetic flux of 8 × 10−4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

बेरीज
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उत्तर

Given:-

Magnetic flux linked with each turn, ϕ = 8 × 10−4 Wb

Number of turns, n = 200

Current, i = 4 A

Self-inductance is calculated as:-

\[L = \left( \frac{n\phi}{i} \right)\]

\[=\left( \frac{200}{4} \right) \times (8) \times ( {10}^{- 4} )\]

= 4 × 10−2 H

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पाठ 38: Electromagnetic Induction - Exercises [पृष्ठ ३१२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 38 Electromagnetic Induction
Exercises | Q 67 | पृष्ठ ३१२

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