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प्रश्न
A lab assistant prepared a solution by adding a calculated quantity of HCl gas at 25°C to get a solution with [H3O+]= 4 × 10−5 M. Is the solution neutral (or) acidic (or) basic.
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उत्तर
[H3O+] = 4 × 10−5 M
pH = – log10 [H3O+]
pH = – log10 [4 × 10−5]
pH = – log10 [4] – log10 [10−5]
pH = – 0.6020 – (– 5)
= – 0.6020 + 5
pH = 4.398
Therefore, the solution is acidic.
Since pH is less than 7, the solution is acidic.
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संबंधित प्रश्न
Calculate the pH of the following solution:
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The pH of 10−8 M of HCl is ______.
Following solutions were prepared by mixing different volumes of NaOH of HCl different concentrations.
i. 60 mL `"M"/10` HCl + 40 mL `"M"/10` NaOH
ii. 55 mL `"M"/10` HCl + 45 mL `"M"/10` NaOH
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iv. 100 mL `"M"/10` HCl + 100 mL `"M"/10` NaOH
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