Question

A. hot solid of mass 60 g at 100°C is placed in 150 g of water at 20° C. The final steady temperature recorded is 25°C. Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 J kg^-1 °C^-1]

Answer 1

Mass of hot solid m = 60 gm, at 100 C

Mass of water, m2 = 150 gm, at 20 C

Final temperature = 25 C

By principle of calorimetry,

Heat given = Heat taken

⇒ m₁c₁ΔQ₁ = m₂c₂ΔQ₂ 

⇒ 60 × c × (100 - 25) = 150 × 4.2 × (25 - 20)

⇒ ∴ Required specific heat, c₁ = 0.7 J/ gm °C