Advertisements
Advertisements
प्रश्न
A garden is in the form of a rhombus whose side is 30 metres and the corresponding altitude is 16 m. Find the cost of levelling the garden at the rate of Rs 2 per m2.
Advertisements
उत्तर
Given:
Side of the rhombus shaped garden = 30 m
Altitude = 16 m
Now, area of a rhombus = side x Altitude
\[ \therefore\text{ Area of the given garden }=30\times16=480 m^2 \]
\[ {\text{ Also, it is given that the rate of levelling the garden is } \text{ Rs 2 per }1m}^2 .\]
\[ \therefore {\text{ Total cost of levelling the complete garden of area }480 m}^2 =480\times2= \text{ Rs }960\]
संबंधित प्रश्न
The floor of a building consists of 3000 tiles, which are rhombus shaped, and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if the cost per m2 is ₹ 4.
The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.
A rectangular grassy plot is 112 m long and 78 m broad. It has a gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs 4.50 per square metre.
Find the area of a rhombus, each side of which measures 20 cm and one of whose diagonals is 24 cm.
The cost of fencing a square field at 60 paise per metre is Rs 1200. Find the cost of reaping the field at the rate of 50 paise per 100 sq. metres.
The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonals of the rhombus is 22 cm, find the length of the other diagonal.
Find the area of the following regular hexagon.
Polygon ABCDE is divided in different parts as shown in figure. If AD = 8 cm, AH = 6 cm, AG = 4 cm, AF = 3 cm and BF = 2 cm, CH = 3cm, EG = 2.5 cm. Then find the area of the polygon.


A regular hexagon is inscribed in a circle of radius r. The perimeter of the regular hexagon is ______.
