Advertisements
Advertisements
प्रश्न
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the side along the road. It the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.

Advertisements
उत्तर
Perpendicular distance between two parallel sides = 100 m
Area of field = 10500 m2
Let the length of the side along the road = x
The length of the side along the river = 2x
Area of trapezium = 12 × (first side + second side) × perpendicular distance
10500 = `1/2` (x + 2x) × 100
10500 = 3x × 50
`x = 10500/(50×3)`
x = 70
Therefore, length of the side along the river = 2x
= 2 × 70
= 140 m
संबंधित प्रश्न
The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.
The floor of a building consists of 3000 tiles, which are rhombus shaped, and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor if the cost per m2 is ₹ 4.
There is a pentagonal shaped park as shown in the figure. For finding its area Jyoti and Kavita divided it in two different ways.

Find the area of this park using both ways. Can you suggest some other way of finding its area?
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?
The area of a rhombus is 240 cm2 and one of the diagonal is 16 cm. Find another diagonal.
A rectangular grassy plot is 112 m long and 78 m broad. It has a gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs 4.50 per square metre.
Find the area of a rhombus, each side of which measures 20 cm and one of whose diagonals is 24 cm.
Find the area of the field in the form of a rhombus, if the length of each side be 14 cm and the altitude be 16 cm.

A regular hexagon is inscribed in a circle of radius r. The perimeter of the regular hexagon is ______.
