Advertisements
Advertisements
प्रश्न
A galvanometer of resistance 100 Ω gives a full-scale deflection for a potential difference of 200 mV.
- What must be the resistance connected to convert the galvanometer into an ammeter of the range 0-200 mA?
- Determine resistance of the ammeter.
Advertisements
उत्तर
(i) Given: G = 100 Ω; I = 200 mA;
Vg = 200 mV;
Resistance to be connected to the galvanometer to convert to an ammeter:
S = `("I"_"g""G")/(("I"-"I"_"g"))`
Here Ig= `("V"_"g")/"G"`
= `(200 " mV")/(100 " Ω")`
= 2 mA
S = `(2 × 10^(-3) × 100)/((0.2-0.002))`
S = 1.01 Ω
(ii) `1/"R" = 1/100 + 1/1.01`
R = 0.999 Ω
APPEARS IN
संबंधित प्रश्न
An ideal voltmeter has _______.
(A) low resistance
(b) high resistance
(C) infinite resistance
(D) zero resistance
Increasing the current sensitivity of a galvanometer may not necessarily increase its voltage sensitivity. Explain, giving reason.
A moving coil galvanometer has a resistance of 25Ω and gives a full scale deflection for a current of 10mA. How will you convert it into a voltmeter having range 0 - 100 V?
Figure shows two circuits each having a galvanometer and a battery of 3V.
When the galvanometers in each arrangement do not show any deflection, obtain the ratio R1/R2.
State the principle of the working of a moving coil galvanometer, giving its labeled diagram ?
Outline the necessary steps to convert a galvanometer of resistance RG into an ammeter of a given range ?
A galvanometer of resistance 100 Ω gives a full-scale deflection for a current of 10−5 A. To convert it into an ammeter capable of measuring up to 1 A we should connect a resistance of ______.
When a galvanometer is shunted with a 4 Ω resistance, the deflection is reduced to one-fifth. If the galvanometer is further shunted with a 2 Ω wire. The further reduction (find the ratio of decrease in current to the previous current) in the deflection will be (the main current remains the same)
Explain in brief the basic construction of a moving-coil table galvanometer whit a neat labelled diagram.
A moving coil galvanometer of resistance 55 Ω produces a full scale deflection for a current of 250 mA. How will you convert it into an ammeter with a range of 0 - 3A?
