Advertisements
Advertisements
प्रश्न
A cuboidal box is 5 cm by 5 cm by 4 cm. Find its surface area.
Advertisements
उत्तर
\[\text { The dimensions of the cuboidal box are 5 cm }\times 5 cm \times 4 cm . \]
\[\text { Surface area of the cuboidal box = 2 } \times (\text { length } \times \text { breadth + breadth } \times \text { height + length }\times \text { height })\]
\[ = 2 \times (5 \times 5 + 5 \times 4 + 5 \times 4)\]
\[ = 2 \times (25 + 20 + 20)\]
\[ = 130 {cm}^2\]
APPEARS IN
संबंधित प्रश्न
Parveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimensions 4 m × 3 m?
A closed iron tank 12 m long, 9 m wide and 4 m deep is to be made. Determine the cost of iron sheet used at the rate of Rs. 5 per metre sheet, sheet being 2 m wide.
A cuboidal wooden block contains 36 cm3 wood. If it be 4 cm long and 3 cm wide, find its height.
A tea-packet measures 10 cm × 6 cm × 4 cm. How many such tea-packets can be placed in a cardboard box of dimensions 50 cm × 30 cm × 0.2 m?
How many planks each of which is 3 m long, 15 cm broad and 5 cm thick can be prepared from a wooden block 6 m long, 75 cm broad and 45 cm thick?
The dimensions of an oil tin are 26 cm × 26 cm × 45 cm. Find the area of the tin sheet required for making 20 such tins. If 1 square metre of the tin sheet costs Rs 10, find the cost of tin sheet used for these 20 tins.
The walls and ceiling of a room are to be plastered. The length, breadth and height of the room are 4.5 m, 3 m and 350 cm, respectively. Find the cost of plastering at the rate of Rs 8 per square metre.
The surface area of a cuboid formed by joining face to face 3 cubes of side x is 3 times the surface area of a cube of side x.
