Question

The perimeter of a floor of a room is 30 m and its height is 3 m. Find the area of four walls of the room.

Answer 1

\[\text { Perimeter of the floor of the room = 30 m } \]

\[\text { Height of the oom = 3 m } \]

\[\text { Perimeter of a rectangle = 2 } \times  { \text { (length + breadth) }} = 30 m \]

\[\text { So, area of the four walls = 2} \times \text { (length  }\times\text {  height + breadth  }\times \text { height) }\]

\[ = 2 \times \text { (length + breadth) } \times \text { heigh }t\]

\[ = 30 \times 3 = 90 m^2\]