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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

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प्रश्न

A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

संख्यात्मक
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उत्तर

Inductance of inductor, L = 44 mH = 44 × 10−3 H

Supply voltage, V = 220 V

Frequency, v = 50 Hz

Angular frequency, ω = 2πv

Inductive reactance, XL = ω L = 2πvL

= 2π × 50 × 44 × 10−3 Ω

The rms value of current is given as:

`"I" = "V"/"X"_"L"`

= `220/(2pi xx 50 xx 44 xx 10^-3)`

= 15.92 A

Hence, the rms value of the current in the circuit is 15.92 A.

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पाठ 7: Alternating Current - EXERCISES [पृष्ठ २००]

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एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 7 Alternating Current
EXERCISES | Q 7.3 | पृष्ठ २००
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 7 Alternating Current
Exercise | Q 7.3 | पृष्ठ २६६

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