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प्रश्न
A 1 cm straight segment of a conductor carrying 1 A current in x direction lies symmetrically at origin of Cartesian coordinate system. The magnetic field due to this segment at point (1m, 1m, 0) is ______.
पर्याय
`1.0 xx 10^-9 hat k T`
`-1.0 xx 10^-9 hat k T`
`5.0/sqrt2 xx 10^-10 hat k T`
`-5.0/sqrt2 xx 10^-10 hat k T`
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उत्तर
A 1 cm straight segment of a conductor carrying 1 A current in x direction lies symmetrically at origin of Cartesian coordinate system. The magnetic field due to this segment at point (1m, 1m, 0) is `bbunderline(-5.0/sqrt2 xx 10^-10 hat k T)`.
Explanation:
Given: I = 1 A
dl = 0.01 m
Observation point: P(1, 1, 0)
r = `sqrt(1^2 + 1^2)`
= `sqrt 2`
Using Biot-Savart law:
dB = `(mu_0)/(4 pi) (Idl xx r)/r^3`
For a small element at x = 0,
dl × r = `dx hat k`
Magnetic field (B) = `(mu_0)/(4 pi) * (dx hat k)/r^3`
= `(10^-7 xx 0.01)/(sqrt 2)^3 hat k`
= `10^-9/(2 sqrt 2) hat k`
= `(-5.02)/sqrt 2 xx 10^-10 hat k T`
