Advertisements
Advertisements
प्रश्न
`1/27 x^3 - y^3 + 125z^3 + 5xyz`
Advertisements
उत्तर
`1/27 x^3 - y^3 + 125z^3 + 5xy`
`= (x/3)^3 + (-y)^3 + (5z)^3 - 3 xx x/3 (-y)(5z)`
`= (x/3 + (-y) + 5z)((x/3)^2 + (-y)^2 + (5z)^2 - x/3 (-y)- (-y)5z - 5z (x/3))`
`= (x/3 - y + 5z)(x^2/9 + y^2 + 25z^2 + (xy)/3 + 5xyz - 5/3 zx)`
`∴ 1/27 x^3 - y^3 + 125z^3 + 5xyz = (x/3 - y + 5z)(x^2/9 + y^2 + 25z^2 + (xy)/3 + 5yz - 5/3 zx)`
APPEARS IN
संबंधित प्रश्न
Factorize `2a^2 + 2 sqrt6ab + 3b^2`
Factorize `7(x - 2y)^2 - 25(x - 2y) + 12`
Factorize the following expressions
1- 27a3
Factorize the following expressions:
a3 + 3a2b + 3ab2 + b3 - 8
The factors of x4 + x2 + 25 are
Divide: 4x3 - 2x2 by - x
Divide: 6x2 + 5x - 6 by 2x + 3
Divide: 9x2 - 24xy + 16y2 by 3x- 4y
Write in the form of an algebraic expression:
Surface area of a cube is six times the square of its edge.
Number of terms in the expression a2 + bc × d is ______.
