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Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई chapter 24 - Graphical Solution [Solution of Simultaneous Linear Equations, Graphically] [Latest edition]

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Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई chapter 24 - Graphical Solution [Solution of Simultaneous Linear Equations, Graphically] - Shaalaa.com
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Solutions for Chapter 24: Graphical Solution [Solution of Simultaneous Linear Equations, Graphically]

Below listed, you can find solutions for Chapter 24 of CISCE Selina for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई.


Exercise 24 (A)Exercise 24 (B)TEST YOURSELF
Exercise 24 (A) [Page 362]

Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई 24 Graphical Solution [Solution of Simultaneous Linear Equations, Graphically] Exercise 24 (A) [Page 362]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 362

Point (k, 2) lies on the line x − 4y = 2; the value of k is ______.

  • 10

  • −6

  • −10

  • 6

1. (b)Page 362

The line y = mx − 8 passes through the point (5, 2); the value of m is ______.

  • 1

  • 2

  • −2

  • −1

1. (c)Page 362

The line 5x − 2y − 10 = 0 intersects x-axis at point P. The co-ordinates of point P are ______.

  • (0, 2)

  • (0, −2)

  • (2, 0)

  • (−2, 0)

1. (d)Page 362

The line 5x − 4y − 20 = 0 intersects y-axis at point A. The co-ordinates of point A are ______.

  • (−5, 0)

  • (5, 0)

  • (0, 5)

  • (0, −5)

1. (e)Page 362

The point (0, 0) lies on ______.

  • x-axis

  • y-axis

  • x-axis or y-axis

  • x-axis and y-axis both

2. (i)Page 362

Draw the graph for the equation, given below :
x = 5

2. (ii)Page 362

Draw the graph for the equation, given below :
x + 5 = 0

2. (iii)Page 362

Draw the graph for the equation, given below :
y = 7

2. (iv)Page 362

Draw the graph for the equation, given below :
y + 7 = 0

2. (v)Page 362

Draw the graph for the equation, given below :
2x + 3y = 0

2. (vi)Page 362

Draw the graph for the equation, given below:
3x + 2y = 6

2. (vii)Page 362

Draw the graph for the equation, given below :
x - 5y + 4 = 0

2. (viii)Page 362

Draw the graph for the equation, given below :
5x + y + 5 = 0

3. (i)Page 362

Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(1)/(3) x +(1)/(5) y = 1`.

3. (ii)Page 362

Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(2x + 15)/(3) = y - 1`

4.Page 362

Draw the graph of the straight line given by the equation 4x - 3y + 36 = 0
Calculate the area of the triangle formed by the line drawn and the co-ordinate axes.

5.Page 362

Draw the graph of the equation 2x - 3y - 5 = 0
From the graph, find:
(i) x1, the value of x, when y = 7
(ii) x2, the value of x, when y = - 5.

6.Page 362

Draw the graph of the equation
4x + 3y + 6 = 0
From the graph, find :
(i) y1, the value of y, when x = 12.
(ii) y2, the value of y, when x = - 6.

7.Page 362

Use the table given below to draw the graph.

X - 5 - 1 3 b 13
Y - 2 a 2 5 7

From your graph, find the values of 'a' and 'b'.
State a linear relationship between the variables x and y.

8.Page 362

Draw the graph obtained from the table below:

X a 3 - 5 5 c - 1
Y - 1 2 b 3 4 0

Use the graph to find the values of a, b and c. State a linear relation between the variables x and y.

9.Page 362

A straight line passes through the points (2, 4) and (5, - 2). Taking 1 cm = 1 unit; mark these points on a graph paper and draw the straight line through these points. If points (m, - 4) and (3, n) lie on the line drawn; find the values of m and n.

10.Page 362

Draw the graph (straight line) given by equation x - 3y = 18. If the straight line is drawn passes through the points (m, - 5) and (6, n); find the values of m and n.

Exercise 24 (B) [Page 365]

Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई 24 Graphical Solution [Solution of Simultaneous Linear Equations, Graphically] Exercise 24 (B) [Page 365]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 365

The point of intersection of lines x = 8 and y − 8 = 0 is ______.

  • (8, 8)

  • (8, −8)

  • (−8, 8)

  • (−8, −8)

1. (b)Page 365

For line y = 20 + 2x, if x = 20, the value of y is ______.

  • 40

  • 60

  • 80

  • 0

1. (c)Page 365

A point that lies on the line 2x − 3y = 4 can be taken as ______.

  • (−5, −2)

  • (−5, 2)

  • (5, 2)

  • (5, −2)

1. (d)Page 365

The line x + 5 = 0 ______.

  • is parallel to x-axis

  • is parallel to y-axis

  • passes through (0, 0)

  • passes through (5, 0)

1. (e)Page 365

The lines y − 2 = 0 and 2x + 3y = 12 cut each other at point ______.

  • (−3, 2)

  • (3, −2)

  • (−3, −2)

  • (3, 2)

2. (i)Page 365

Solve, graphically, the following pairs of equation :
x - 5 = 0 
y + 4 = 0

2. (ii)Page 365

Solve, graphically, the following pairs of equation :
2x + y = 23
4x - y = 19

2. (iii)Page 365

Solve, graphically, the following pairs of equation :
3x + 7y = 27
8 - y = `(5)/(2)x`

2. (iv)Page 365

Solve, graphically, the following pairs of equations :
`(x + 1)/(4) = (2)/(3)(1 - 2y)`

`(2 + 5y)/(3) = x/(7) -2`

3.Page 365

Solve graphically the simultaneous equations given below. Take the scale as 2 cm = 1 unit on both the axes.
x - 2y - 4 = 0
2x + y = 3

4.Page 365

Use graph paper for this question. Draw the graph of 2x - y - 1 = 0 and 2x + y = 9 on the same axes. Use 2 cm = 1 unit on both axes and plot only 3 points per line. Write down the coordinates of the point of intersection of the two lines.

5.Page 365

Use graph paper for this question. Take 2 cm = 2 units on x-axis and 2 cm = 1 unit on y-axis.
Solve graphically the following equation:
3x + 5y = 12; 3x - 5y + 18 = 0 (Plot only three points per line)

6.Page 365

Use graph paper for this question. Take 2 cm = 1 unit on both the axes.

  1. Draw the graphs of x + y + 3 = 0 and 3x - 2y + 4 = 0. Plot only three points per line.
  2. Write down the coordinates of the point of intersection of the lines.
  3. Measure and record the distance of the point of intersection of the lines from the origin in cm.
7.Page 365

The sides of a triangle are given by the equations y - 2 = 0; y + 1 = 3 (x - 2) and x + 2y = 0.
Find, graphically : 
(i) the area of a triangle;
(ii) the coordinates of the vertices of the triangle.

8.Page 365

By drawing a graph for each of the equations 3x + y + 5 = 0; 3y - x = 5 and 2x + 5y = 1 on the same graph paper; show that the lines given by these equations are concurrent (i.e. they pass through the same point). Take 2 cm = 1 unit on both the axes.

9.Page 365

Using a scale of 1 cm to 1 unit for both the axes, draw the graphs of the following equations: 6y = 5x + 10, y = 5x - 15.
From the graph find :
(i) the coordinates of the point where the two lines intersect;
(ii) the area of the triangle between the lines and the x-axis.

10. (i)Page 365

The cost of manufacturing x articles is Rs. (50 + 3x). The selling price of x articles is Rs. 4x.

On a graph sheet, with the same axes, and taking suitable scales draw two graphs, first for the cost of manufacturing against no. of articles and the second for the selling price against the number of articles.

Use your graph to determine:
No. of articles to be manufactured and sold to break even (no profit and no loss).

10. (ii)Page 365

The cost of manufacturing x articles is Rs.(50 + 3x). The selling price of x articles is Rs. 4x.

On a graph sheet, with the same axes, and taking suitable scales draw two graphs, first for the cost of manufacturing against no. of articles and the second for the selling price against the number of articles.

Use your graph to determine:
The profit or loss made when (a) 30 (b) 60 articles are manufactured and sold.

TEST YOURSELF [Pages 366 - 367]

Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई 24 Graphical Solution [Solution of Simultaneous Linear Equations, Graphically] TEST YOURSELF [Pages 366 - 367]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 366

For the line 2x − y = 7 and for x = 3 the value of y is ______.

  • 1

  • −1

  • 5

  • −5

1. (b)Page 366

The line x + 3y + 2 = 0 passes through the point (4, k); then the value of k is ______.

  • 2

  • 1

  • −1

  • −2

1. (c)Page 366

Lines x − 5 = 0 and y + 3 = 0 intersect each other at point ______.

  • (5, 3)

  • (5, −3)

  • (−5, 3)

  • (−5, −3)

1. (d)Page 366

For the line 4x − 7y + 6 = 0 if x = 2; the value of y is ______.

  • 2

  • −2

  • 1

  • −1

1. (e)Page 366

Statement (1): The graph of 2x − 5 = 0 is a line parallel to y-axis.

Statement (2): When the equations of lines are of the form x = ± k (a constant), the lines are parallel to y-axis.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (f)Page 366

Statement (1): The lines of the form ax ± by = 0 always pass through the origin.

Statement (2): On substituting x = 0 and y = 0; we get a × 0 ± b × 0 = 0.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (g)Page 366

Assertion (A): y + 5 = 0 is the equation of the line parallel to x-axis and at a distance of 5 unit in the negative direction from it.

Reason (R): For all the points on the line y = a (a constant), the value of abscissa is a.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

1. (h)Page 366

Assertion (A): For the line 3x + 4y = 7, the abscissa is `- 3/4`.

Reason (R): For abscissa of a point, y = 0 and 3x + 4y = 7 ⇒ `x = 7/3`.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

2.Page 366

Find the distance of point (8, −4) from y-axis.

3.Page 366

Three vertices of parallelogram ABCD are A(−5, −1), B(3, −1) and C(1, −6). Use graphical method to find the co-ordinates of fourth vertex D.

4.Page 366

In the given figure, ABC is an equilateral triangle. Find the co-ordinates of A.

5.Page 366

Draw the graph of 3x + 2y = 6. Use the graph drawn to find the area of triangle formed by the line drawn and the co-ordinate axes.

6. (i)Page 366

Use the graphical method to find the value of k, if:
(k, -3) lies on the straight line 2x + 3y = 1

6. (ii)Page 366

Use the graphical method to find the value of k, if:
(5, k - 2) lies on the straight line x - 2y + 1 = 0

7.Page 367

Find graphically, the vertices of the triangle whose sides have the equations 2y - x = 8; 5y - x = 14 and y - 2x = 1 respectively. Take 1 cm = 1 unit on both the axes.

8.Page 367

Using the same axes of co-ordinates and the same unit, solve graphically :
x + y = 0 and 3x - 2y = 10.
(Take at least 3 points for each line drawn).

9.Page 367

Solve graphically, the following equations.
x + 2y = 4; 3x - 2y = 4.
Take 2 cm = 1 unit on each axis.
Also, find the area of the triangle formed by the lines and the x-axis.

10.Page 367

Use the graphical method to find the value of 'x' for which the expressions `(3x + 2)/(2) and (3)/(4)x - 2`

11.Page 367

The course of an enemy submarine, as plotted on rectangular co-ordinate axes, gives the equation 2x + 3y = 4. On the same axes, a destroyer's course is indicated by the graph x - y = 7. Use the graphical method to find the point at which the paths of the submarine and the destroyer intersect?

Case-Study Based Question:

1.Page 367

An equation which can be put in the form ax + by + c = 0 is called a linear equation, where:

  1. x and y are variables.
  2. a, b and c are real numbers and
  3. a and b are both not zero.

On drawing a graph for the two linear equations on the same plane, it is seen that only one of the following three possibilities can happen:

  1. the two lines intersect at one point.
  2. the two lines do not intersect (i.e. the lines are parallel to each other)
  3. the two lines coincide (i.e. the lines have infinite number of solutions).

For two linear equations \[a_1x + b_1y + c_1 = 0\] and \[a_2x + b_2y + c_2 = 0\],

  1. \[\frac{a_1}{a_2} \neq \frac{b_1}{b_2}\] ⇒ lines intersect each other ⇒ lines have a unique solution
  2. \[\frac{a_1}{a_2} = \frac{b_1}{b_2}\] ⇒ lines do not intersect at all ⇒ lines are parallel to each other ⇒ lines have no solution}
  3. \[\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}\] ⇒ lines are coincident ⇒ lines have infinite solutions

On comparing the ratios \[\frac{a_1}{a_2}, \frac{b_1}{b_2}\text{ and }\frac{c_1}{c_2}\], find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident.

  1. 7x − 5y + 10 = 0
    6x + 2y − 15 = 0
  2. 5x + 2y + 8
    15x + 6y + 24 = 0
  3. 4x − 8y + 9 = 0
    2x − 4y + 7 = 0
  4. x − 2y = 0
    3x − 4y − 20 = 0
  5. 2x + 3y − 9 = 0
    4x + 6y − 18 = 0
  6. x + 2y − 4 = 0
    2x + 4y − 12 = 0

Solutions for 24: Graphical Solution [Solution of Simultaneous Linear Equations, Graphically]

Exercise 24 (A)Exercise 24 (B)TEST YOURSELF
Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई chapter 24 - Graphical Solution [Solution of Simultaneous Linear Equations, Graphically] - Shaalaa.com

Selina solutions for कन्साइस मैथमैटिक्स [अंग्रेजी] कक्षा ९ आईसीएसई chapter 24 - Graphical Solution [Solution of Simultaneous Linear Equations, Graphically]

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