Question

Find graphically, the vertices of the triangle whose sides have the equations 2y - x = 8; 5y - x = 14 and y - 2x = 1 respectively. Take 1 cm = 1 unit on both the axes.

Answer 1

2y - x = 8;
y = `(8 + x)/(2);`
The table of 2y - x = 8 is

X	- 6	- 2	0
Y	1	3	4

5y - x = 14
⇒ x = 5y - 14
The table of x = 5y - 14 is

X	- 9	- 4	1
Y	1	2	3

y - 2x = 1
⇒ y = 1 + 2x
The table of y - 2x = 1 is

X	2	- 2	0
Y	5	- 3	1

Now plotting the points on a graph and we get the following required graph:

Thus, the verticles of the triangle ΔABC are: A(- 4, 2), B(1, 3) and C(2, 5).