Advertisements
Advertisements
प्रश्न
Solve the following equations graphically :
2x - 6y + 10 = 0
3x - 9y + 25 = 0
Advertisements
उत्तर
2x - 6y + 10 = 0
3x - 9y + 25 = 0
2x - 6y + 10 = 0 _________(1)
3x - 9y + 25 = 0 _________(2)
2x - 6y + 10 = 0
⇒ x = `(6y - 10)/(2)`
= 3y - 5
Corresponding values of x and y can be tabulated as :
| x | -5 | -2 | 1 |
| y | 0 | 1 | 2 |
Plotting points (-5, 0),(-2, 1), (1, 2) and joining them, we get a line l1 which is the graph of the equation (1).
Again, 3x - 9y + 25 = 0
⇒ x = `(9y - 25)/(3)`
Corresponding values of x and y can be tabulated as :
| x | 0 | `(-25)/(3)` = 8.33 |
| y | `(25)/(9)` =2.77 | 0 |
Plotting points `(0, 25/9), ((-25)/3, 0)` and joining them, we get a line l2 which is the graph of the equation (2).
The line l1 and l2 do not intersect each other.
Thus, the given equations do not have any solution.
APPEARS IN
संबंधित प्रश्न
The sides of a triangle are given by the equations y - 2 = 0; y + 1 = 3 (x - 2) and x + 2y = 0.
Find, graphically :
(i) the area of a triangle;
(ii) the coordinates of the vertices of the triangle.
Find graphically, the vertices of the triangle whose sides have the equations 2y - x = 8; 5y - x = 14 and y - 2x = 1 respectively. Take 1 cm = 1 unit on both the axes.
Use the graphical method to find the value of 'x' for which the expressions `(3x + 2)/(2) and (3)/(4)x - 2`
Solve the following equations graphically :
2x + 4y = 7
3x + 8y = 10
Find graphically the vertices of the triangle, whose sides are given by 3y = x + 18, x + 7y = 22 and y + 3x = 26.
Solve the following system of equations graphically:
6x - 3y + 2 = 7x + 1
5x + 1 = 4x - y + 2
Also, find the area of the triangle formed by these lines and x-axis in each graph.
Solve graphically
x + y = 7, x – y = 3
Solve graphically
3x + 2y = 4, 9x + 6y – 12 = 0
Solve graphically
x – y = 0, y + 3 = 0
Solve graphically
y = 2x + 1, y + 3x – 6 = 0
