Advertisements
Advertisements
प्रश्न
Solve the following equations graphically :
x + 4y + 9 = 0
3y = 5x - 1
Advertisements
उत्तर
x + 4y + 9 = 0
3y = 5x - 1
x + 4y + 9 _______(1)
3y = 5x - 1_______(2)
Now, x + 4y = -9
⇒ x = -9 - 4y
Corresponding values of x and y can be tabulated as :
| x | 4 | -1 | -5 |
| y | -3 | -2 | -1 |
Plotting points (4, -3), (-1, -2) and (-5, -1) and joining them, we geta line l1 which is the graph of equation (!).
Again, 3y = 5 x -1
⇒ y = `(5x - 1)/(3)`
Corresponding values of x and y can be tabulated as :
| x | -4 | -1 | 5 |
| y | -7 | -2 | 8 |
Plotting points (-4, -7), (-1, -2), (5, 8) and joining them we get a line l2 which is the graph of equation (2).
The two line l1 and l2 intersect at a unique point (-1, -2). Thus, x = -1 and y = -2 is the unique solution of the given equations.
APPEARS IN
संबंधित प्रश्न
Find graphically, the vertices of the triangle whose sides have the equations 2y - x = 8; 5y - x = 14 and y - 2x = 1 respectively. Take 1 cm = 1 unit on both the axes.
Solve graphically, the following equations.
x + 2y = 4; 3x - 2y = 4.
Take 2 cm = 1 unit on each axis.
Also, find the area of the triangle formed by the lines and the x-axis.
Use the graphical method to find the value of 'x' for which the expressions `(3x + 2)/(2) and (3)/(4)x - 2`
Solve the following equations graphically :
x = 4
`(3x)/(3) - y = 5`
Solve the following equations graphically :
2x - 6y + 10 = 0
3x - 9y + 25 = 0
Find graphically the vertices of the triangle, whose sides have the equations 2y - x = 8, 5y -x = 14 and y = 2x - 1.
Find graphically the vertices of the triangle, whose sides are given by 3y = x + 18, x + 7y = 22 and y + 3x = 26.
Solve the following system of linear equations graphically :
4x - 5y - 20 = 0
3x + 3y - 15 = 0
Determine the vertices of the triangle formed by the lines, represented by the above equations and the y-axis.
Solve graphically
x + y = 7, x – y = 3
Solve graphically
y = 2x + 1, y + 3x – 6 = 0
