HSC Science कक्षा ११ - Tamil Nadu Board of Secondary Education Question Bank Solutions for Chemistry

Enthalpy of neutralization is always a constant when a strong acid is neutralized by a strong base: account for the statement.

Derive the relation between ∆H and ∆U for an ideal gas. Explain each term involved in the equation.

Bond order of a species is 2.5 and the number of electons in its bonding molecular orbital is formd to be 8 The no. of electons in its antibonding molecular orbital is

Non – Zero dipole moment is shown by ______.

Define bond order.

What is dipole moment?

Calculate the enthalpy change for the reaction \[\ce{Fe2O3 + 3CO -> 2Fe + 3CO2}\] from the following data.

\[\ce{2Fe + 3/2O2 -> Fe2O3}\]; ΔH = −741 kJ

\[\ce{C + 1/2O2 -> CO}\]; ΔH = −137 kJ

\[\ce{C + O2-> CO2}\]; ΔH = −394.5 kJ

Linear form of carbondioxide molecule has two polar bonds. Yet the molecule has Zero dipole moment. Why?

The standard enthalpies of formation of SO₂ and SO₃ are −297 kJ mol⁻¹ and −396 kJ mol⁻¹ respectively. Calculate the standard enthalpy of reaction for the reaction: \[\ce{SO2 + 1/2O2 -> SO3}\]

Define bond energy.

Explain resonance with reference to a carbonate ion.

Explain the bond formation in ethylene.

Explain the bond formation in acetylene.

CO₂ and H₂O both are triatomic molecule but their dipole moment values are different. Why?

Which one of the following has the highest bond order?

1. N₂
2. N₂⁺
3. N₂^–

Describe Fajan’s rule.

The number of stereoisomers of 1, 2 – dihydroxy cyclopentane

Which of the following is optically active?

The isomer of ethanol is ______.

Which one of the following shows functional isomerism?