हिंदी

HSC Science (Computer Science) १२ वीं कक्षा - Maharashtra State Board Question Bank Solutions

Advertisements
[object Object]
[object Object]
विषयों
मुख्य विषय
अध्याय

Please select a subject first

Advertisements
Advertisements
< prev  10201 to 10220 of 10495  next > 

Disintegration rate of a sample is 1010 per hour at 20 hours from the start. It reduces to 6.3 x 109 per hour after 30 hours. Calculate its half-life and the initial number of radioactive atoms in the sample.

[15] Structure of Atoms and Nuclei
Chapter: [15] Structure of Atoms and Nuclei
Concept: undefined >> undefined

The isotope \[\ce{^57Co}\] decays by electron capture to \[\ce{^57Fe}\] with a half-life of 272 d. The \[\ce{^57Fe}\] nucleus is produced in an excited state, and it almost instantaneously emits gamma rays.
(a) Find the mean lifetime and decay constant for 57Co.
(b) If the activity of a radiation source 57Co is 2.0 µCi now, how many 57Co nuclei does the source contain?

c) What will be the activity after one year?

[15] Structure of Atoms and Nuclei
Chapter: [15] Structure of Atoms and Nuclei
Concept: undefined >> undefined

Advertisements

A source contains two species of phosphorous nuclei, \[\ce{_15^32P}\] (T1/2 = 14.3 d) and \[\ce{_15^33P}\] (T1/2 = 25.3 d). At time t = 0, 90% of the decays are from \[\ce{_15^32P}\]. How much time has to elapse for only 15% of the decays to be from \[\ce{_15^32P}\]?

[15] Structure of Atoms and Nuclei
Chapter: [15] Structure of Atoms and Nuclei
Concept: undefined >> undefined

Before the year 1900 the activity per unit mass of atmospheric carbon due to the presence of 14C averaged about 0.255 Bq per gram of carbon.
(a) What fraction of carbon atoms were 14C?
(b) An archaeological specimen containing 500 mg of carbon, shows 174 decays in one hour. What is the age of the specimen, assuming that its activity per unit mass of carbon when the specimen died was equal to the average value of the air? The half-life of 14C is 5730 years.

[15] Structure of Atoms and Nuclei
Chapter: [15] Structure of Atoms and Nuclei
Concept: undefined >> undefined

The maximum speed of a particle executing S.H.M. is 10 m/s and maximum acceleration is 31.4 m/s2. Its periodic time is ______ 

[5] Oscillations
Chapter: [5] Oscillations
Concept: undefined >> undefined

A simple pendulum is inside a spacecraft. What will be its periodic time? 

[5] Oscillations
Chapter: [5] Oscillations
Concept: undefined >> undefined

What is Solenoid?

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

What is Toroid?

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

A solenoid of length 50 cm of the inner radius of 1 cm and is made up of 500 turns of copper wire for a current of 5 A in it. What will be the magnitude of the magnetic field inside the solenoid? 

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

Magnetic field lines can be entirely confined within the core of a toroid, but not within a straight solenoid Why?

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

A toroid of 4000 turns has an outer radius of 26 cm and an inner radius of 25 cm. If the current in the wire is 10 A. Calculate the magnetic field of the toroid. 

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

A solenoid of length π m and 5 cm in diameter has a winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its centre along the radius.

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

Using Ampere's Law, derive an expression for the magnetic induction inside an ideal solenoid carrying a steady current.

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

Obtain an expression for the decay law of radioactivity. Hence show that the activity A(t) =λNO e-λt.  

[15] Structure of Atoms and Nuclei
Chapter: [15] Structure of Atoms and Nuclei
Concept: undefined >> undefined

Obtain an expression for magnetic induction of a toroid of ‘N’ turns about an axis passing through its centre and perpendicular to its plane.

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

A conducting rod along the equator is 1 m long and carries a current of 15 A from east to west. The magnitude of Earth's magnetic field at the equator is `4/3 xx 10^(-4)` T. The magnitude and direction of the force on the rod are ______.

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

Why does hot soap water help to remove tough stains on a fabric?

[2] Mechanical Properties of Fluids
Chapter: [2] Mechanical Properties of Fluids
Concept: undefined >> undefined

The half-life of `""_82^210Pb` is 22.3 y. How long will it take for its activity 0 30% of the initial activity?

[15] Structure of Atoms and Nuclei
Chapter: [15] Structure of Atoms and Nuclei
Concept: undefined >> undefined

For a solenoid and a toroid, the number of turns per unit length is n and the respective interior volume is V. The self inductance is proportional to n2 and V for ______.

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined

A current of 10 A passes through a coil having 5 turns and produces magnetic field at the centre of the coil having magnitude 0.5 x 10-4 T. Calculate diameter of the coil.

0 = 4π x 10-7 Wb/Am)  

[10] Magnetic Fields Due to Electric Current
Chapter: [10] Magnetic Fields Due to Electric Current
Concept: undefined >> undefined
< prev  10201 to 10220 of 10495  next > 
Advertisements
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×