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PUC Science कक्षा ११ - Karnataka Board PUC Question Bank Solutions for Mathematics

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Mathematics
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In an A.P. the first term is 2 and the sum of the first five terms is one fourth of the next five terms. Show that 20th term is −112.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If S1 be the sum of (2n + 1) terms of an A.P. and S2 be the sum of its odd terms, then prove that: S1 : S2 = (2n + 1) : (n + 1).

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

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Find an A.P. in which the sum of any number of terms is always three times the squared number of these terms.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If the sum of n terms of an A.P. is nP + \[\frac{1}{2}\] n (n − 1) Q, where P and Q are constants, find the common difference.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The sums of n terms of two arithmetic progressions are in the ratio 5n + 4 : 9n + 6. Find the ratio of their 18th terms.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

The sums of first n terms of two A.P.'s are in the ratio (7n + 2) : (n + 4). Find the ratio of their 5th terms.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If \[\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\] are in A.P., prove that:

\[\frac{b + c}{a}, \frac{c + a}{b}, \frac{a + b}{c}\] are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If \[\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\] are in A.P., prove that:

a (b +c), b (c + a), c (a +b) are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a2, b2, c2 are in A.P., prove that \[\frac{a}{b + c}, \frac{b}{c + a}, \frac{c}{a + b}\] are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c is in A.P., then show that:

 a2 (b + c), b2 (c + a), c2 (a + b) are also in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c is in A.P., then show that:

b + c − a, c + a − b, a + b − c are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c is in A.P., then show that:

bc − a2, ca − b2, ab − c2 are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If \[\frac{b + c}{a}, \frac{c + a}{b}, \frac{a + b}{c}\] are in A.P., prove that:

\[\frac{1}{a}, \frac{1}{b}, \frac{1}{c}\] are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If \[\frac{b + c}{a}, \frac{c + a}{b}, \frac{a + b}{c}\] are in A.P., prove that:

 bc, ca, ab are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c is in A.P., prove that:

 (a − c)2 = 4 (a − b) (b − c)

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c is in A.P., prove that:

a2 + c2 + 4ac = 2 (ab + bc + ca)

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If a, b, c is in A.P., prove that:

 a3 + c3 + 6abc = 8b3.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If \[a\left( \frac{1}{b} + \frac{1}{c} \right), b\left( \frac{1}{c} + \frac{1}{a} \right), c\left( \frac{1}{a} + \frac{1}{b} \right)\] are in A.P., prove that abc are in A.P.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

Show that x2 + xy + y2, z2 + zx + x2 and y2 + yz + z2 are consecutive terms of an A.P., if x, y and z are in A.P. 

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined

If x, y, z are in A.P. and A1 is the A.M. of x and y and A2 is the A.M. of y and z, then prove that the A.M. of A1 and A2 is y.

[8] Sequence and Series
Chapter: [8] Sequence and Series
Concept: undefined >> undefined
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