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Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

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Mathematics
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In a triangle OAB,\[\angle\]AOB = 90º. If P and Q are points of trisection of AB, prove that \[{OP}^2 + {OQ}^2 = \frac{5}{9} {AB}^2\]

[10] Vectors
Chapter: [10] Vectors
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Prove that: If the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus. 

[10] Vectors
Chapter: [10] Vectors
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(Pythagoras's Theorem) Prove by vector method that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 

[10] Vectors
Chapter: [10] Vectors
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Prove by vector method that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.

[10] Vectors
Chapter: [10] Vectors
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Prove using vectors: The quadrilateral obtained by joining mid-points of adjacent sides of a rectangle is a rhombus. 

[10] Vectors
Chapter: [10] Vectors
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Prove that the diagonals of a rhombus are perpendicular bisectors of each other. 

[10] Vectors
Chapter: [10] Vectors
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Prove that the diagonals of a rectangle are perpendicular if and only if the rectangle is a square. 

[10] Vectors
Chapter: [10] Vectors
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If AD is the median of ∆ABC, using vectors, prove that \[{AB}^2 + {AC}^2 = 2\left( {AD}^2 + {CD}^2 \right)\] 

[10] Vectors
Chapter: [10] Vectors
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If the median to the base of a triangle is perpendicular to the base, then triangle is isosceles. 

[10] Vectors
Chapter: [10] Vectors
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In a quadrilateral ABCD, prove that \[{AB}^2 + {BC}^2 + {CD}^2 + {DA}^2 = {AC}^2 + {BD}^2 + 4 {PQ}^2\] where P and Q are middle points of diagonals AC and BD. 

[10] Vectors
Chapter: [10] Vectors
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Differentiate xsinx+(sinx)cosx with respect to x.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
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\[\int\limits_0^k \frac{1}{2 + 8 x^2} dx = \frac{\pi}{16},\] find the value of k.

[7] Integrals
Chapter: [7] Integrals
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\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.

[7] Integrals
Chapter: [7] Integrals
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\[\int_\pi^\frac{3\pi}{2} \sqrt{1 - \cos2x}dx\]
[7] Integrals
Chapter: [7] Integrals
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If \[f\left( a + b - x \right) = f\left( x \right)\] , then prove that

\[\int_a^b xf\left( x \right)dx = \left( \frac{a + b}{2} \right) \int_a^b f\left( x \right)dx\]
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Find the distance of the point  \[2 \hat{i} - \hat{j} - 4 \hat{k}\]  from the plane  \[\vec{r} \cdot \left( 3 \hat{i}  - 4 \hat{j}  + 12 \hat{k}  \right) - 9 = 0 .\]

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Show that the points \[\hat{i}  - \hat{j}  + 3 \hat{k}  \text{ and }  3 \hat{i}  + 3 \hat{j}  + 3 \hat{k} \] are equidistant from the plane \[\vec{r} \cdot \left( 5 \hat{i}  + 2 \hat{j}  - 7 \hat{k}  \right) + 9 = 0 .\]

  
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the distance of the point (2, 3, −5) from the plane x + 2y − 2z − 9 = 0.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
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Find the equations of the planes parallel to the plane x + 2y − 2z + 8 = 0 that are at a distance of 2 units from the point (2, 1, 1).

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Show that the points (1, 1, 1) and (−3, 0, 1) are equidistant from the plane 3x + 4y − 12z + 13 = 0.

 
[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined
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