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(English Medium) ICSE Class 10 - CISCE Question Bank Solutions for Mathematics

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Mathematics
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Rs. 7500 is divided equally among a certain number of children. Had there been 20 less children, each would have receive Rs 100 more. Find the original number of children. 

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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2x articles cost Rs. (5x + 54) and (x + 2) similar articles cost Rs. (10x – 4), find x.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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A shopkeeper buys a certain number of books for Rs 960. If the cost per book was Rs 8 less, the number of books that could be bought for Rs 960 would be 4 more. Taking the original cost of each book to be Rs x, write an equation in x and solve it to find the original cost of each book.

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A piece of cloth costs Rs. 300. If the piece was 5 metres longer and each metre of cloth costs Rs. 2 less, the cost of the piece would have remained unchanged. How long is the original piece of cloth and what is the rate per metre?

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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The hotel bill for a number of people for an overnight stay is Rs. 4800. If there were 4 more, the bill each person had to pay would have reduced by Rs. 200. Find the number of people staying overnight. 

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A person was given Rs. 3000 for a tour. If he extends his tour programme by 5 days, he must cut down his daily expenses by Rs. 20. Find the number of days of his tour programme.

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Chapter: [5] Quadratic Equations
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Ritu bought a saree for Rs. 60x and sold it for Rs. (500 + 4x) at a loss of x%. Find the cost price.

[5] Quadratic Equations
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Paul is x years old and his father’s age is twice the square of Paul’s age. Ten years hence, the father’s age will be four times Paul’s age. Find their present ages.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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The age of a man is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than three times the age of his son. Find the present age.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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Two years ago, a man’s age was three times the square of his daughter’s age. Three years hence, his age will be four times his daughter’s age. Find their present ages.

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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The length (in cm) of the hypotenuse of a right-angled triangle exceeds the length of one side by 2 cm and exceeds twice the length of another side by 1 cm. Find the length of each side. Also, find the perimeter and the area of the triangle.

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If twice the area of a smaller square is subtracted from the area of a larger square, the result is 14 cm2. However, if twice the area of the larger square is added to three times the area of the smaller square, the result is 203 cm2. Determine the sides of the two squares.

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Solve the following equation by factorisation :

x2 + 6x – 16 = 0

[5] Quadratic Equations
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Solve the following equation by factorisation :

3x2 + 11x + 10 = 0

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Solve the following equation by factorisation :

2x2 + ax – a2= 0

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Solve the following equation by factorisation :

`sqrt(3)x^2 + 10x + 7sqrt(3)` = 0

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Solve the following equation by factorisation :

x(x + 1) + (x + 2)(x + 3) = 42

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Solve the following equation by factorisation :

`(6)/x - (2)/(x - 1) = (1)/(x - 2)`

[5] Quadratic Equations
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Solve the following equation by factorisation :

`sqrt(x + 15) = x + 3`

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Solve the following equation by factorisation :

`sqrt(3x^2 - 2x - 1) = 2x - 2`

[5] Quadratic Equations
Chapter: [5] Quadratic Equations
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