Advertisements
Advertisements
प्रश्न
A piece of cloth costs Rs. 300. If the piece was 5 metres longer and each metre of cloth costs Rs. 2 less, the cost of the piece would have remained unchanged. How long is the original piece of cloth and what is the rate per metre?
Advertisements
उत्तर
The total cost of cloth piece = Rs. 300
Let the length of the piece of cloth in the beginning = x m
Then cost of 1 metre = Rs. `(300)/x`
In second case, length of cloth = (x + 5)
Cost of 1 metre = Rs. `(300)/(x + 5)`
According to the condition,
`(300)/x - (300)/(x + 5)` = 2
⇒ `300(1/x - 1/(x + 5))` = 2
⇒ `300((x + 5 - x)/(x(x + 5)))` = 2
⇒ `(300 xx 5)/(x(x + 5))` = 2
⇒ `(150 xx 5)/(x(x + 5))` = 1 ...(Dividing by 2)
750 = x2 + 5x
⇒ x2 + 5x - 750 = 0
⇒ x2 + 30x - 25x - 750 = 0
⇒ (x + 30) -25(x + 30) = 0
⇒ (x + 30)(x - 25) = 0
Either x + 30 = 0,
then x = -30
which is not possible being negative
or
x - 25 = 0,
then x = 25
∴ Length of cloth piece in the begining = 25 metres
and rate per metre = Rs. `(300)/(25)` = Rs. 12.
APPEARS IN
संबंधित प्रश्न
The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
Solve the following quadratic equations by factorization:
`(x + 3)/(x - 2) - (1 - x)/x = 17/4; x ≠ 0, 2`
The sum of the squares of the two consecutive odd positive integers as 394. Find them.
The sum of two numbers is 18. The sum of their reciprocals is 1/4. Find the numbers.
A passenger train takes one hour less for a journey of 150 km if its speed is increased by 5 km/hr from its usual speed. Find the usual speed of the train.
The sum of a natural number and its reciprocal is `65/8`. Find the number.
Solve equation using factorisation method:
x2 – 10x – 24 = 0
Harish made a rectangular garden, with its length 5 metres more than its width. The next year, he increased the length by 3 metres and decreased the width by 2 metres. If the area of the second garden was 119 sq m, was the second garden larger or smaller ?
Forty years hence, Mr. Pratap’s age will be the square of what it was 32 years ago. Find his present age.
Solve the quadratic equation: x2 – 2ax + (a2 – b2) = 0 for x.
