English Medium कक्षा ९ - CBSE Question Bank Solutions for Mathematics

If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)² =

If \[x = 7 + 4\sqrt{3}\] and xy =1, then \[\frac{1}{x^2} + \frac{1}{y^2} =\]

If \[x + \sqrt{15} = 4,\] then \[x + \frac{1}{x}\] = 

If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=

If x= \[\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}\] and y = \[\frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} - \sqrt{2}}\] , then x² + y +y² =

\[\frac{1}{\sqrt{9} - \sqrt{8}}\] is equal to

The value of \[\frac{\sqrt{48} + \sqrt{32}}{\sqrt{27} + \sqrt{18}}\] is 

If \[\frac{5 - \sqrt{3}}{2 + \sqrt{3}} = x + y\sqrt{3}\] , then

If x = \[\sqrt[3]{2 + \sqrt{3}}\] , then \[x^3 + \frac{1}{x^3} =\]

The value of \[\sqrt{3 - 2\sqrt{2}}\] is 

The value of \[\sqrt{5 + 2\sqrt{6}}\] is

If \[\sqrt{2} = 1 . 4142\] then \[\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\] is equal to

If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is

The positive square root of \[7 + \sqrt{48}\] is 

If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]

If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]

If \[x - \frac{1}{x} = - 1\]  find the value of  \[x^2 + \frac{1}{x^2}\]

Find the cube of the following binomials expression :

\[\frac{1}{x} + \frac{y}{3}\]

Find the cube of the following binomials expression :

\[\frac{3}{x} - \frac{2}{x^2}\]

Find the cube of the following binomials expression :

\[2x + \frac{3}{x}\]