Advertisements
Advertisements
प्रश्न
Find the following product:
(3x + 2y) (9x2 − 6xy + 4y2)
Advertisements
उत्तर
In the given problem, we have to find the value of (3x + 2y) (9x2 − 6xy + 4y2)
Given (3x + 2y) (9x2 − 6xy + 4y2)
We shall use the identity `a^3 + b^3 = (a+b)(a^2 + b^2 - ab)`
We can rearrange the `(3x + 2y)(9x^3 - 6xy + 4y^2)`as
` = (3x + 2y)[(3x)^2 - (3x)(2y)+(2y)^2]`
` = (3x)^2 + (2y)^3`
` = (3x) xx (3x) xx (3x) + (2y) xx 2y xx (2y)`
` = 27x^3 + 8y^3`
Hence the Product value of `(3x+ 2y) (9x^2 - 6xy + 4y^2)`is `27x^3 + 8y^3`.
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(x + 8) (x – 10)
Use suitable identity to find the following product:
(3 – 2x) (3 + 2x)
Factorise the following using appropriate identity:
4y2 – 4y + 1
Evaluate the following using identities:
(1.5x2 − 0.3y2) (1.5x2 + 0.3y2)
Evaluate the following using identities:
(399)2
Simplify the following:
322 x 322 - 2 x 322 x 22 + 22 x 22
if `x^2 + 1/x^2 = 79` Find the value of `x + 1/x`
Evaluate of the following:
`(10.4)^3`
If x + \[\frac{1}{x}\] = then find the value of \[x^2 + \frac{1}{x^2}\].
If \[x + \frac{1}{x} = 2\], then \[x^3 + \frac{1}{x^3} =\]
If a1/3 + b1/3 + c1/3 = 0, then
Use the direct method to evaluate :
`("a"/2-"b"/3)("a"/2+"b"/3)`
Expand the following:
(m + 8) (m - 7)
Expand the following:
(3x + 4) (2x - 1)
If p + q = 8 and p - q = 4, find:
pq
Simplify:
(2x + y)(4x2 - 2xy + y2)
Factorise the following:
9y2 – 66yz + 121z2
Factorise the following:
`(2x + 1/3)^2 - (x - 1/2)^2`
Find the following product:
(x2 – 1)(x4 + x2 + 1)
Without actually calculating the cubes, find the value of:
(0.2)3 – (0.3)3 + (0.1)3
