Advertisements
Advertisements
प्रश्न
If `x + (1)/x = "p", x - (1)/x = "q"`; find the relation between p and q.
Advertisements
उत्तर
`x + (1)/x = "p", x - (1)/x = "q"`
`(x + 1/x)^2`
= `x^2 + (1)/x^2 +2`
⇒ p2 = `x^2 + (1)/x^2 + 2`
⇒ `x^2 + (1)/x^2 = "p"^2 - 2` ...(1)
Also, `(x - 1/x)^2`
= `x^2 + (1)/x^2 - 2`
⇒ `"q"^2 = x^2 + (1)/x^2 - 2`
⇒ `x^2 + (1)/x^2 = "q"^2 + 2` ...(2)
Equating the value `x^2 + (1)/x^2` from and (2), we get :
p2 - 2 = q2 + 2
⇒ p2 - q2 = 4.
APPEARS IN
संबंधित प्रश्न
Factorise the following using appropriate identity:
9x2 + 6xy + y2
Evaluate the following using identities:
`(2x+ 1/x)^2`
Evaluate the following using identities:
(2x + y) (2x − y)
If `x + 1/x = sqrt5`, find the value of `x^2 + 1/x^2` and `x^4 + 1/x^4`
Write the expanded form:
`(-3x + y + z)^2`
If a + b = 10 and ab = 21, find the value of a3 + b3
Evaluate, using (a + b)(a - b)= a2 - b2.
15.9 x 16.1
If `"a" + 1/"a" = 6;`find `"a" - 1/"a"`
If p2 + q2 + r2 = 82 and pq + qr + pr = 18; find p + q + r.
Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
