Advertisements
Advertisements
प्रश्न
Find the following product:
(4x − 5y) (16x2 + 20xy + 25y2)
Advertisements
उत्तर
Given (4x − 5y) (16x2 + 20xy + 25y2)
We shall use the identity `(a-b)(a^2 + ab + b^2) = a^3 -b^3`
We can rearrange the (4x − 5y) (16x2 + 20xy + 25y2)as
` =(4x - 5y)[(4x)^2 + (4x)(5y) + (5y)^2]`
` = (4x)^3 - (5y)^3`
` = (4x) xx (4x) xx (4x) + (5y) xx (5y) xx (5y)`
` = 64x^3 - 125y^2`
Hence the Product value of ` (3x+2y)(9x^2 - 6xy + 4y^2)`is `64x^3 - 125y^3`.
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
`(y^2+3/2)(y^2-3/2)`
Without actually calculating the cubes, find the value of the following:
(28)3 + (–15)3 + (–13)3
Evaluate the following:
(98)3
Find the value of 27x3 + 8y3, if 3x + 2y = 14 and xy = 8
If a + b = 10 and ab = 16, find the value of a2 − ab + b2 and a2 + ab + b2
If x + y + z = 8 and xy +yz +zx = 20, find the value of x3 + y3 + z3 −3xyz
\[\frac{( a^2 - b^2 )^3 + ( b^2 - c^2 )^3 + ( c^2 - a^2 )^3}{(a - b )^3 + (b - c )^3 + (c - a )^3} =\]
Evalute : `((2x)/7 - (7y)/4)^2`
If a + `1/a`= 6 and a ≠ 0 find :
(i) `a - 1/a (ii) a^2 - 1/a^2`
Use the direct method to evaluate the following products :
(y + 5)(y – 3)
Expand the following:
(x - 5) (x - 4)
Expand the following:
(a + 3b)2
Evaluate the following without multiplying:
(999)2
If `"a"^2 + (1)/"a"^2 = 14`; find the value of `"a" + (1)/"a"`
Simplify:
(4x + 5y)2 + (4x - 5y)2
Simplify:
(2x + y)(4x2 - 2xy + y2)
Simplify:
(x + 2y + 3z)(x2 + 4y2 + 9z2 - 2xy - 6yz - 3zx)
Simplify:
(3a - 7b + 3)(3a - 7b + 5)
The value of 2492 – 2482 is ______.
