Secondary School (English Medium) (5 to 8) कक्षा ८ - CBSE Question Bank Solutions

Subtract:

\[\frac{2}{3} y^3 - \frac{2}{7} y^2 - 5 \text { from  }\frac{1}{3} y^3 + \frac{5}{7} y^2 + y - 2\]

Subtract: 

\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]

Subtract: 

\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]

Subtract: 

\[\frac{ab}{7} - \frac{35}{3}bc + \frac{6}{5}ac \text { from } \frac{3}{5}bc - \frac{4}{5}ac\]

Subtract 3x − 4y − 7z from the sum of x − 3y + 2z and − 4x + 9y − 11z.

Subtract the sum of 3l − 4m − 7n² and 2l + 3m − 4n² from the sum of 9l + 2m − 3n² and − 3l + m + 4n² .....

Subtract the sum of 2x − x² + 5 and − 4x − 3 + 7x² from 5.

Verify the property: x × y = y × x by taking:

Verify the property: x × y = y × x by taking:

Verify the property: x × y = y × x by taking:

Verify the property: x × y = y × x by taking:

Verify the property: x × (y × z) = (x × y) × z by taking:

Verify the property: x × (y × z) = (x × y) × z by taking:

Verify the property: x × (y × z) = (x × y) × z by taking:

Verify the property: x × (y × z) = (x × y) × z by taking:

Verify the property: x × (y + z) = x × y + x × z by taking:

Verify the property: x × (y + z) = x × y + x × z by taking:

Verify the property: x × (y + z) = x × y + x × z by taking: