Arts (English Medium) कक्षा १२ - CBSE Question Bank Solutions

The slope of the tangent to the curve x = t² + 3t – 8, y = 2t² – 2t – 5 at the point (2,– 1) is

(A) `22/7`

(B) `6/7`

(C) `7/6`

(D) `(-6)/7`

The line y = mx + 1 is a tangent to the curve y² = 4x if the value of m is

(A) 1

(B) 2

(C) 3

(D) 1/2

Evaluate the definite integral:

`int_(-1)^1 (x + 1)dx`

Evaluate the definite integral:

`int_2^3 1/x dx`

Evaluate the definite integral:

`int_1^2 (4x^3 - 5x^2 + 6x + 9)  dx`

Evaluate the definite integral:

`int_0^(pi/4) sin2xdx`

Evaluate the definite integral:

`int_0^(pi/2) cos 2x  dx`

Evaluate the definite integral:

`int_4^5 e^x dx`

Evaluate the definite integral:

`int_0^(pi/4) tan x dx`

Evaluate the definite integral:

`int_(pi/6)^(pi/4) cosec x  dx`

Evaluate the definite integral:

`int_0^1 dx/sqrt(1-x^2)`

Evaluate the definite integral:

`int_0^1 dx/(1+x^2)`

Evaluate the definite integral:

`int_2^3 dx/(x^2 - 1)`

Evaluate the definite integral:

`int_0^(pi/2) cos^2 xdx`

Evaluate the definite integral:

`int_2^3 (xdx)/(x^2 + 1)`

Evaluate the definite integral:

`int_0^1 (2x + 3)/(5x^2 + 1) dx`

Evaluate the definite integral:

`int_0^1 x e^(x^2) dx`

Evaluate the definite integral:

`int_1^2 (5x^2)/(x^2 + 4x + 3)`

Evaluate the definite integral:

`int_0^(pi/4) (2 sec^2 x + x^3  + 2) dx`

Evaluate the definite integral:

`int_0^pi (sin^2  x/2 - cos^2  x/2) dx`