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HSC Science (Electronics) १२ वीं कक्षा - Maharashtra State Board Important Questions

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In ∆ABC, if a = 13, b = 14, c = 15, then find the value of cos B

Appears in 1 question paper
Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

In ∆ABC, prove that `(cos 2"A")/"a"^2 - (cos 2"c")/"c"^2 = 1/"a"^2 - 1/"c"^2`

Appears in 1 question paper
Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

In ∆ABC, if `(2cos "A")/"a" + (cos "B")/"b" + (2cos"C")/"c" = "a"/"bc" + "b"/"ca"`, then show that the triangle is a right angled

Appears in 1 question paper
Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

In ∆ABC, prove that `sin  ((A - B)/2) = ((a - b)/c) cos  C/2` 

Appears in 1 question paper
Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

In ΔABC, prove that `("a"^2sin("B" - "C"))/(sin"A") + ("b"^2sin("C" - "A"))/(sin"B") + ("c"^2sin("A" - "B"))/(sin"C")` = 0

Appears in 1 question paper
Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

In ΔABC, prove that `("b"^2 - "c"^2)/"a" cos"A" + ("c"^2 - "a"^2)/"b" cos"B" + ("a"^2 - "b"^2)/"c" cos "C"` = 0

Appears in 1 question paper
Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

Find the principal solutions of cot θ = 0

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Chapter: [3] Trigonometric Functions
Concept: Trigonometric Equations and Their Solutions

Find the cartesian co-ordinates of the point whose polar co-ordinates are `(1/2, π/3)`.

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Chapter: [3] Trigonometric Functions
Concept: Solutions of Triangle

If 2 tan–1(cos x) = tan–1(2 cosec x). then find the value of x.

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Chapter: [3] Trigonometric Functions
Concept: Trigonometric Equations and Their Solutions

Find the general solution of sin θ + sin 3θ + sin 5θ = 0

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Chapter: [3] Trigonometric Functions
Concept: Trigonometric Equations and Their Solutions

If a line drawn from the point A( 1, 2, 1) is perpendicular to the line joining P(1, 4, 6) and Q(5, 4, 4) then find the co-ordinates of the foot of the perpendicular.

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

The Cartesian equations of line are 3x -1 = 6y + 2 = 1 - z. Find the vector equation of line.

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

The Cartesian equations of line are 3x+1=6y-2=1-z find its equation in vector form.

 

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

The Cartestation equation of  line is `(x-6)/2=(y+4)/7=(z-5)/3` find its vector equation.

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

Find the coordinates of the point where the line through the points A(3, 4, 1) and B(5, 1, 6) crosses the XZ plane. Also find the angle which this line makes with the XZ plane.

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space
 

Find the value of p, so that the lines `l_1:(1-x)/3=(7y-14)/p=(z-3)/2 and l_2=(7-7x)/3p=(y-5)/1=(6-z)/5 ` are perpendicular to each other. Also find the equations of a line passing through a point (3, 2, – 4) and parallel to line l1.

 
Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

Find p and q if the equation px2 – 8xy + 3y2 + 14x + 2y + q = 0 represents a pair of prependicular lines.

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: General Second Degree Equation

Let `A(bara)` and `B(barb)` be any two points in the space and `R(barr)` be a point on the line segment AB dividing it internally in the ratio m : n, then prove that `bar r=(mbarb+nbara)/(m+n)`. Hence find the position vector of R which divides the line segment joining the points A(1, –2, 1) and B(1, 4, –2) internally in the ratio 2 : 1.

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

Find the vector equation of the lines which passes through the point with position vector `4hati - hatj +2hatk` and is in the direction of `-2hati + hatj + hatk`

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space

 The equation of a line is 2x -2 = 3y +1 = 6z -2 find the direction ratios and also find the vector equation of the line. 

Appears in 1 question paper
Chapter: [4] Pair of Straight Lines
Concept: Equation of a Line in Space
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