Definitions [8]
A wavefront is a surface of constant phase.
If a point source emits waves uniformly in all directions, the locus of points which have the same amplitude and vibrate in the same phase is a sphere. This is known as a spherical wave.
At a large distance from the source, a small portion of the spherical wave can be considered as a plane. This is known as a plane wave.
Alignment of dipole moments (permanent or induced) in the direction of an applied electric field is called polarisation.
The periodic variation of intensity of sound between maximum and minimum due to superimposition of two sound waves of same amplitude and slightly different frequencies is called the phenomenon of beats.
The maximum intensity point produced during the formation of beats is called waxing.
The minimum intensity point produced during the formation of beats is called waning.
The variation in intensity of sound with time at a particular position, due to the principle of superposition of two sound waves of slightly different frequencies, is called beats.
Formulae [3]
Defined as dipole moment per unit volume:
\[P=\frac{\text{dipole moment}}{\mathrm{volume}}=np\]
The number of beats formed per second is expressed as ∣v1 − v2∣, i.e., either (v1 − v2) or (v2 − v1), where v1 and v2 are frequencies of the two sound waves.
N = n1 − n2
The beat period is the reciprocal of beat frequency:
T = \[\frac{1}{n_1-n_2}\] or T = \[\frac{1}{|v_1-v_2|}\]
Theorems and Laws [2]
Statement:
When unpolarised light is incident at polarising angle iB on an interface separating air from a medium of refractive index μ, then the reflected light is plane polarised (perpendicular to the plane of incidence), provided:
Additional condition at polarising angle:
i.e., the reflected plane polarised light is at right angles to the refracted light.
OR
Statement:
- When the angle of incidence equals the polarising angle (θB), the reflected and refracted rays are perpendicular to each other.
- "The refractive index of a medium is equal to the tangent of the polarising angle θB."
Prove that the frequency of beats is equal to the difference between the frequencies of the two sound notes giving rise to beats.
Consider two sound waves, having the same amplitude and slightly different frequencies n1 and n2. Let us assume that they arrive in phase at some point x of the medium. The displacement due to each wave at any instant of time at that point is given as
`y_1 = A sin {2pi (n_1t - x/lambda_1)}`
`y_2 = A sin {2pi (n_2t - x/lambda_2)}`
Let us assume for simplicity that the listener is at x = 0.
∴ y1 = A sin (2πn1t) ...(i)
and y2 = A sin (2πn2t) ...(ii)
According to the principle of superposition of waves,
y = y1 + y2
∴ y = A sin (2πn1t) + A sin (2πn2t)
By using formula,
sin C + sin D = 2 sin `((C + D)/2) cos ((C − D)/2)`
y = `A[2sin((2pin_1t + 2pi n_2t)/2 )] cos [((2pin_1t - 2pin_2t)/2)]`
y = `2A sin [2pi ((n_1 + n_2)/2)t] cos [2pi ((n_1 - n_2)/2)t]`
∴ y = `R sin [2pi ((n_1 + n_2)/2)t]`
y = R sin (2πnt) ...(iii)
Where,
R = `2A cos[(2pi(n_1 - n_2))/(2)t]` and n = `(n_1 + n_2)/2`
Equation (iii) is the equation of a progressive wave having frequency `((n_1 + n_2)/2)` and resultant amplitude R.
For waxing,
A = ± 2a
`therefore 2A cos [2pi((n_1 - n_2)/2)t] = +- 2A`
`therefore cos [2pi ((n_1 - n_2)/2)]t = +-( 2A)/(2A)`
`therefore cos [2pi ((n_1 - n_2)/2)]t = +- 1`
This is possible if
`2pi ((n_1 - n_2)/2)t = 0, pi, 2pi, 3pi, ....`
i.e. t = 0, `1/(n_1 - n_2), 2/(n_1 - n_2), 3/(n_1 - n_2), ...`
∴ Period of beat T = `[1/(n_1 - n_2) - 0]`
T = `1/(n_1 - n_2)`
∴ Frequency of beats n = `1/T`
n = n1 − n2
Thus, the frequency of beats is equal to the difference between the frequencies of the two sound notes giving rise to beats.
Key Points
- Beats are formed when two waves of same amplitude but slightly different frequencies superimpose.
- Waxing and waning are alternatively produced.
- The greater the difference in frequency between the two waves, the higher the beat frequency.
Important Questions [14]
- On the Basis of Huygens' Wave Theory of Light Prove That Velocity of Light in a Rarer Medium is Greater than Velocity Of Light in a Denser Medium.
- The Refractive Indices of Water and Diamond Are `4/3` and 2.42 Respectively. Find the Speed of Light in Water and Diamond. (C = 3x108 M/S)
- Explain the Construction of Plane Wavefront Using Huygens’ Principle.
- Explain Refraction of Light on the Basis of Wave Theory. Hence Prove the Laws of Refraction
- Determine the change in wavelength of light during its passage from air to glass. If the refractive index of glass with respect to air is 1.5 and the frequency of light is 3.5 x 1014 Hz
- State Brewster’s law and show that when light is incident at polarizing angle the reflected and refracted rays are mutually perpendicular to each other.
- State Any Four Applications Of Doppler Effect
- Prove that the frequency of beats is equal to the difference between the frequencies of the two sound notes giving rise to beats.
- Two tuning forks of frequencies 320 Hz and 340 Hz are sounded together to produce a sound wave. The velocity of sound in air is 326.4 m/s. Calculate the difference in wavelengths of these waves.
- Find the Velocity of Sound in the Air and Frequency of the Tuning Fork
- In Doppler Effect of Light, the Term “Red Shift” is Used for
- Doppler Effect is Not Applicable When
- The Working of Radar is Based on
- Apparent Frequency of the Sound Heard by a Listener is Less than the Actual Frequency of Sound Emitted by Source. in this Case
