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प्रश्न
You are given four organic compounds “A”, “B” , “C” and “D”. The compounds “A”, “B” and “C” form an orange-red precipitate with 2, 4 DNP reagent. Compounds “A” and “B” reduce Tollen’s reagent while compounds “C” and “D” do not. Both “B” and “C” give a yellow precipitate when heated with iodine in the presence of NaOH. Compound “D” gives brisk effervescence with sodium bicarbonate solution. Identify “A”, “B”, “C” and “D” given the number of carbon atoms in three of these carbon compounds is three while one has two carbon atoms. Give an explanation for our answer.
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उत्तर
A, B and C contain carbonyl group as they give positive 2, 4 DNP test
A and B are aldehydes as aldehydes reduce Tollen’s reagent
C is a ketone, as it contains carbonyl group but does not give positive Tollen’s test
C is a methyl ketone as it gives positive iodoform test
B is an aldehyde that gives positive iodoform test
D is a carboxylic acid
Since the number of carbons in the compounds A, B, C and D is three or two
B is CH3CHO as this is only aldehyde which gives a positive iodoform test
The remaining compounds A, C and D have three carbons
A is \[\ce{CH3CH2CHO}\], C is \[\ce{CH3COCH3}\] and D is \[\ce{CH3CH2COOH}\]
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संबंधित प्रश्न
Predict the products of the following reactions :

Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?
Which of the following tests/reactions is given by aldehydes as well as ketones?
A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.
- Identify (A), (B) and (C).
- Write the reaction of B with Tollen’s reagent.
- Write the equation for iodoform test for C.
- Write down the equation for aldol condensation reaction of B and C.
The major products formed in the following reaction sequence A and B are:

An organic compound neither reacts with neutral ferric chloride solution nor with Fehling solution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is:
An organic compound 'A' with molecular formula C5H8O2 is reduced to n-pentane with hydrazine followed by heating with NaOH and glycol. 'A' forms a dioxime with hydroxylamine and gives a positive iodoform and Tollen's test. Identify 'A' and give its reaction for iodoform and Tollen's test.
An organic compound 'A' with the molecular formula C4H8O2 undergoes acid hydrolysis to form two compounds 'B' and 'C'. Oxidation of 'C' with acidified potassium permanganate also produces 'B'. Sodium salt of 'B' on heating with soda lime gives methane.
- Identify 'A', 'B' and 'C'.
- Out of 'B' and 'C', which will have higher boiling point? Give reason.
Fehling’s solution ‘A’ is ______.
