Advertisements
Advertisements
प्रश्न
Write the rate law for the following reaction.
A reaction that is `3/2` order in x and zero order in y.
Advertisements
उत्तर
\[\ce{3/2 x + y (excess) -> products}\]
`-3/2 ("d"["x"])/"dt" = "k" ["x"]^(3/2)`
APPEARS IN
संबंधित प्रश्न
Answer the following in brief.
Derive the integrated rate law for the first-order reaction,
\[\ce{A_{(g)} -> B_{(g)} + C_{(g)}}\] in terms of pressure.
Solve
The half-life of a first-order reaction is 1.7 hours. How long will it take for 20% of the reactant to react?
Answer the following in brief.
What are the units of the rate constant?
Write order of the following reaction:
\[\ce{2NH_{3(g)} -> N_{2(g)} + 3H_{2(g)}}\]
What is half life of first order reaction if time required to decrease concentration of reactants from 0.8 M to 0.2 M is 12 hours?
A zero order reaction is 20% complete in 20 minutes. Calculate the value of the rate constant. In what time will the reaction be 80% complete?
For first order reaction the concentration of reactant decreases from 0.2 to 0.1 M in 100 minutes. What is the rate constant of the reaction?
The slope of a graph, log [A]t versus 't' for a first order reaction is −2.5 × 10−3 s−1. The rate constant for the reaction is ____________.
Half-life of first-order reaction \[\ce{X -> Y + Z}\] is 3 minutes. What is the time required to reduce the concentration of 'X' by 90 % of it's initial concentration?
A first order reaction takes 10 minute for 30% completion. Find rate constant of the reaction.
