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प्रश्न
Write the following number using positive indices.
`(2/7)^-2`
योग
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उत्तर
It is known that `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(2/7)^-2`
`= 1/(2/7)^2`
`= (7/2)^2`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
`((1/7)^-3)^4`
Solve: `((2/5)^(-2))^3`.
Using the power rule, (37)−2 = 35
Solve for x: `(5^5 xx 5^(-4) xx 5^x)/(5^12)` = 5−5
Simplify using law of exponents.
(xm)0
240 + 240 is equal to
62 × 6m = 65, find the value of ‘m’
`[((-1)/4)^16]^2 = ((-1)/4)^-`
34 > 43
Arrange in ascending order:
25, 33, 23 × 2, (33)2, 35, 40, 23 × 31
