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प्रश्न
Write the following number using positive indices.
`(2/7)^-2`
योग
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उत्तर
It is known that `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(2/7)^-2`
`= 1/(2/7)^2`
`= (7/2)^2`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
`(3^4)^-2`
Simplify:
`[(5/8)^3]^-2`
Simplify:
`[(3/4)^6]^1`
Simplify:
`[(2/5)^-3]^2`
Using the power rule, (37)−2 = 35
Solve for x: `(2^(2x - 1))/(2^(x + 2))` = 4
Simplify using law of exponents.
(64)3
`(6/13)^10 ÷ [(6/13)^5]^2 = (6/13)^-`
(–3)4 = –12
Arrange in ascending order:
25, 33, 23 × 2, (33)2, 35, 40, 23 × 31
